Remove the last character in a string with ksh script

How can I remove the last character in a string with ksh script if that character is 'x'?
LVL 35
YZlatAsked:
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woolmilkporcCommented:
positive:

str="abcdex"

if [[ "${str#"${str%?}"}" = "x" ]] ; then
 str="${str%?}"
fi
echo "$str"

-> abcde

negative (same script, different string):

str="abcdey"

if [[ "${str#"${str%?}"}" = "x" ]] ; then
 str="${str%?}"
fi
echo "$str"

-> abcdey
0
simon3270Commented:
Or just

    str=${str%x}
0

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YZlatAuthor Commented:
simon, does your code remove only trailin gx or any x in the variable str?

for instance if str="axbcdx", will it remove both x's or just the x at the end?
0
simon3270Commented:
Just the trailing one.

To remove all x's you'd do
    str=${str//x/}
0
YZlatAuthor Commented:
Thank you!
0
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