Sql date compare query

Below is some sample table data from tblWagers

wager        StartDateTime   (stored as datetime)                    

400           2013-09-06 13:29:35.000          

200           2013-09-06 07:29:35.000      

1520         2013-09-07 00:59:35.000        

500           2013-09-07 01:01:35.000      



I am trying to write a query that will return all records with a startdatetime on or after 8am on the current date up to and including any records with a startdatetime  of 1 am  or earlier the following day

(For the purposes of this example, let's assume current date is 09/06/2013.  Given that,  the query is looking for 8am on 9/16/2013 to 1am on 9/17/2013)

So in the example above I would expect the query to return

 

400           2013-09-06 13:29:35.000    

1520         2013-09-07 00:59:35.000        

Not sure how to format where clause for correct date compare
johnnyg123Asked:
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Give this a whirl in SSMS, then once you verify it works modify to meet your needs.

btw Which casino?
CREATE TABLE #tmp (wager int, StartDateTime datetime)
INSERT INTO #tmp (wager, StartDateTime)
VALUES 
	(400, '2013-09-11 13:29:35.000'),           
	(200, '2013-09-11 07:29:35.000'),     
	(1520, '2013-09-12 00:59:35.000'),       
	(500, '2013-09-12 01:01:35.000')  


SELECT wager, StartDateTime
FROM #tmp
WHERE StartDateTime BETWEEN CAST(CAST(CAST(GETDATE() as date) as varchar(10)) + ' 08:00:00.000' as datetime)
	and CAST(CAST(CAST(DATEADD(d, 1, GETDATE()) as date) as varchar(10)) + ' 01:00:00.000' as datetime)

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Guessing there is a more elegant way to pull this off without all the CASTs, but none come to mind.
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PortletPaulfreelancerCommented:
These results:
WAGER	STARTDATETIME
400	September, 06 2013 13:29:35+0000
1520	September, 07 2013 00:59:35+0000

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Produced by:
-- truncate time on getdate()
-- dateadd(day, datediff(day,0, <<data-here>> ), 0)

declare @s datetime, @f datetime
set @s = dateadd(hour, 8, dateadd(day, datediff(day,0, getdate() ), 0) )
set @f = dateadd(hour, 17, @s)

select
*
from yourtable
where ( StartDateTime >= @s and StartDateTime < @f )
;

select
*
from yourtable
where ( StartDateTime >= dateadd(hour, 8, dateadd(day, datediff(day,0, getdate() ), 0) )
    and StartDateTime < dateadd(hour, 25, dateadd(day, datediff(day,0, getdate() ), 0) )
      )
;

Open in new window

Question:
is <date> 01:00:00 included in the results?
if it is then
change <
to <=
in the queries above

http://sqlfiddle.com/#!3/e8002/3
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Thanks for the grade.  Good luck with your project.  -Jim
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Microsoft SQL Server 2008

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