String manipulation

I have a string that has a network path along with a filename assigned to it.
'\\dev01\company011\_fileserver\content\Image\VCSJK_1bd00b4f-c26e-4d01-84c6-d0848aa258d5_concert.jpg'

I need the filename stripped from the string
'VCSJK_1bd00b4f-c26e-4d01-84c6-d0848aa258d5_concert.jpg'

I am trying to get everything from the right of 'Image\' but I figured Id post it as well

Thats it!!

Thanks
jknj72Asked:
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sdstuberCommented:
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jknj72Author Commented:
I need it in VB now....The last one was an Oracle question
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sdstuberCommented:
if your vb is talking to an oracle database, you can still use the original answer

but vb.net syntax might look something like this...

right(your_string, your_string.length - instrrev(your_string,'\'))
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slightwv (䄆 Netminder) Commented:
Back in the day, I picked up a vb.net function.  Not sure if I borrowed it off the internet (probably where I got it) or from some other source:

	Function GetLastRightOf(LookFor as String, myString as String) as String
		Dim StrPos as Integer
		StrPos = myString.LastIndexOf(LookFor)
		Return myString.SubString(StrPos + 1)
	End Function

Open in new window


Then you would just call:
GetLastRightOf("\","\\dev01\company011\_fileserver\content\Image\VCSJK_1bd00b4f-c26e-4d01-84c6-d0848aa258d5_concert.jpg")
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jknj72Author Commented:
I actually  got it using

Mid(url, url.LastIndexOf("\") + 2)

I would have given you points but it didnt work..


Thanks anyway sdstub
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sdstuberCommented:
sorry,

 I put the '\'  in single quotes
it should have been double quotes "\"
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willaienCommented:
System.IO.Path.GetFileName(FullPath)

There are methods for this specific case, why not use them?
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jknj72Author Commented:
Haha that should have been what I was looking for Will. A little late though. Thanks
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Mel-Leo RosalCommented:
Dim strTemp() As String
Dim sANSWER As String
Dim strInput As String = "\\dev01\company011\_fileserver\content\Image\VCSJK_1bd00b4f-c26e-4d01-84c6-d0848aa258d5_concert.jpg"

strTemp = Split(strInput, "\")
sANSWER = strTemp(UBound(strTemp))

MsgBox(sANSWER)

Open in new window

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jknj72Author Commented:
i figured it out but thanks anyway
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