Reversing digits of an integer in Java

Greetings, esteemed experts!

I'm teaching myself Java (after decades of being a database guy). I'm going through a book, and one of the exercises is asking to write a method that reverses the digits of an integer and returns it as a String.

It sounded pretty simple, and I wrote code below, but the method isn't returning anything. This is probably extremely simple, but I'm missing it.

// Exercise 6.26: Exercise6_26.java
// Reverse an integer string
package Chapter6;
import java.util.Scanner;

public class Exercise6_26 {
   public static void main( String[] args ) {
      int reverseThis = 0;
      while (reverseThis != -1) {
         Scanner input = new Scanner( System.in );
         System.out.print( "Enter an integer (-1 to quit): " );
         reverseThis = input.nextInt();
         if (reverseThis == -1) break;

         System.out.printf("reversed(%d) = %s\n\n", reverseThis, reverseIt(reverseThis));
      } // while (side1 != -1)
   } // end main

   // reverse an integer and return a String
   public static String reverseIt( int reverseIt ) {
      StringBuilder sb = new StringBuilder(reverseIt);
      return sb.reverse().toString();
   } // end method reverseIt 

} // public class Exercise6_24

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Here's my output:

Enter an integer (-1 to quit): 1234
reversed(1234) = 

Enter an integer (-1 to quit): -1

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Thanks for your help!
DaveSlash
LVL 18
Dave FordSoftware Developer / Database AdministratorAsked:
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CPColinSenior Java ArchitectCommented:
You're calling this StringBuilder constructor:

http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#StringBuilder%28int%29

You'll want to use Integer.toString() to turn that int into a String before you pass it to the StringBuilder constructor.
0
krakatoaCommented:
You can do it like this also :

class ReverseNumber {

static Integer number = 123456;
static Integer scratchNum = number;
static int workingint = 0;
static StringBuilder s = new StringBuilder();
static int n = 0;
static int m = 0;

  public static void main(String[] args){

for(int a=0;a<(int)number.bitCount(number);a++){

	n = (scratchNum.intValue()/10)*10;
	m = scratchNum.intValue();
	workingint = (m-n);
	s.append(String.valueOf(workingint));
	scratchNum = new Integer(scratchNum.intValue()/10);
}

System.out.println(s.toString());

  }


}

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0
Tomas Helgi JohannssonCommented:
Hi!

The constructor you are calling creates a empty string with the capacity of the size given in int.
http://docs.oracle.com/javase/6/docs/api/java/lang/StringBuilder.html
http://docs.oracle.com/javase/7/docs/api/java/lang/Integer.html

In your orginal code you can modify your function like this.

public static String reverseIt( int reverseIt ) {
      StringBuilder sb = new StringBuilder(Integer.toString(reverseIt));
      return sb.reverse().toString();
   } // end method reverseIt

Regards,
    Tomas Helgi
0

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Dave FordSoftware Developer / Database AdministratorAuthor Commented:
Thank you! That worked beautifully.
0
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