asked on

How does conditional part work in for loop.

Case 1:
main()
{
      int a=0;
      for(;a;)
      {
            printf("Hello");
      }
}
Output: /*It doesn't print Hello*/

Case 2:
main()
{
      for(;0;)
      {
            printf("Hello");
      }
}

/*prints hello for one time*/

Why this kind of output comes in Turbo C++

ozo

Either you or Turbo C++ must have done something wrong.

searchsanjaysharma

ASKER

Hi ozo,

You may try with your expertise and check , since i found this an exception, hence i posted that.

ozo

Neither case should print Hello at all.

searchsanjaysharma

ASKER

Yes, its there, but when u execute it doesnt happen.

ozo

What is where and what doesn't happen when u execute what?

Julian Hansen

Try compiling to assembler and see what the output is - that should give you some idea of what it is doing.

Can confirm this does not happen in other compilers.

ASKER CERTIFIED SOLUTION

Frank Helk

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evilrix

>> Why this kind of output comes in Turbo C++
There are only two possible reasons:

1. The code example you've provided isn't actually what you're building and running
2. Your compiler is defective

I very much doubt it's number 2 so I have to conclude that it's number 1.

Put simply, I concur with ozo.

Please copy and paste, verbatim, the code you are building.

>> Can confirm this does not happen in other compilers.
Phew! :)

sarabande

i once had a semicolon ; after the for statement.

for(;<some_lengthy_condition_which_was_false>;);
{
      some_code();
}

Open in new window

and some_code() function was called once.

it took me some time to find out what was wrong ...

Sara

searchsanjaysharma

ASKER