Sub String

I am trying to extract number from rows in a table
I used
select substring(Note,Charindex('Num'.Note,1)+3,3)
from MyTable
but it is not perfect.
For eq.

ID                             Note
---------                     ------------------------------------------------------------
1                              fname=san,lname=jj,Num=12,address=abcdef
2                              fname=san,lname=jj,address=abcdef
3                              fname=san,lname=jj,address=abcdef,Num=123

ID                            Num#
-------                       -----------------------
1                              12
2                                0
3                               123

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Kent DyerIT Security Analyst SeniorCommented:
First thing, locate the records that only have Num..
select substring(Note,Charindex('Num'.Note,1)+3,3)
from MyTable where Note like '%Num%'

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Unfortunately, SQL Server does not have a native SPLIT Function like VB/VBA/etc.  Did find the following -

SELECT PARSENAME(REPLACE('Hello John Smith', ' ', '.'), 2)

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This would be good information to start with..

{url removed from this post, see admin note below}
I'm suggesting use of "cross apply" here because it reduces the number of time you need to use charindex. The results of the cross apply may then be used in a case expression to produce (I believe) the wanted result.
    | ID |   NUM# | POS1 | POS2 | COLUMN_4 |
    |  1 |     12 |   24 |   26 |        2 |
    |  2 | (null) |    4 |   19 |       15 |
    |  3 |    123 |   39 |   19 |      -20 |

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         , CASE
             WHEN pos1 > 4 and pos2 > pos1 THEN substring(Note,pos1,pos2-pos1)
             WHEN pos1 > 4 and pos1 > pos2 THEN substring(Note,pos1,3)
             ELSE NULL 
           END AS "Num#"

      /* only included to inspect 'how' */
      , pos1
      , pos2
      , pos2-pos1

    FROM MyTable
    CROSS apply (
                  SELECT Charindex('Num=',Note,1) + 4, Charindex(',address',Note,1)
                ) AS ca1 (pos1, pos2)

    	([ID] varchar(9), [Note] varchar(60))
    	([ID], [Note])
    	('1', 'fname=san,lname=jj,Num=12,address=abcdef'),
    	('2', 'fname=san,lname=jj,address=abcdef'),
    	('3', 'fname=san,lname=jj,address=abcdef,Num=123')



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SanPrgAuthor Commented:
Thanks  PortletPaul,
It is Awesome.
Thanks, all the best, Paul
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