How to get System.Diagnostic.Process to launch Windows Task Scheduler

I have a simple button click in a WPF application that launches the Windows Task Scheduler.  

        private void LaunchTaskScheduler_Click(object sender, RoutedEventArgs e)
        {
            var taskscheduler = Environment.GetFolderPath(Environment.SpecialFolder.SystemX86) + @"\taskschd.msc";

            Process p = new Process();
            p.StartInfo.UseShellExecute = false;
            p.StartInfo.FileName = taskscheduler;
            p.StartInfo.CreateNoWindow = true;

            p.Start();         
        }

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I have used this approach in the past in the WinForms world with no issue.  Can anyone see/know what I am doing wrong?
Todd710Asked:
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Fernando SotoRetiredCommented:
Hi Todd710;

In order to execute this type of application, taskschd.msc, you will need to use the true value in the UseShellExecute parameter as follows.

p.StartInfo.UseShellExecute = true;

A false value here will only run executable file types, .exe, the shell knows what to do with this type.
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Todd710Author Commented:
You are absolutely correct!  Thanks for the help!  Additionally I discovered that you can do this too:

var taskscheduler = Environment.GetFolderPath(Environment.SpecialFolder.SystemX86) + @"\taskschd.msc";

System.Diagnostics.Process.Start(taskscheduler);

Which does exactly what you said as it uses the default ShellExecute.
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