replace #Value with 0

I am struggling with a formula and would appreciate some help.

P2 contains a date. I need to find how many days between today and the date in P2

So if P2 is 15/11/13 and today is 13/10/13 return 33 but if P2 is Blank, return Blank.

I need to say :

If P2 is Blank return blank but if P2 is not blank return P2- Today()

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JagwarmanAuthor Commented:
replace #Value with 0 should read

replace #Value with Blank
This should do it:


you may find the following more bullet proof:


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JagwarmanAuthor Commented:
Thanks The_Barman exactly what I need.
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