We help IT Professionals succeed at work.
Get Started
Display randomly selected images in PHP
Hello Experts,
I am trying to display 5 random images, each time I click a button.
The following is my HTML code:
And the following is my PHP code:
As usual, my HTML code is not communicating to my PHP code and my HTML page is not displaying any images now.
How can I display the multiple images in HTML page using PHP and when I click a button, change the images, without displaying any duplicates? Is my approach going to a right direction...?
For this practice, I am using the images of a deck of playing cards and put them into a folder named "cards". I thought about that writing array for every single card, like "2c.gif", "2d.gif", "2h.gif", "2s.gif", and while I was searching online, I found a piece of code, which might be the way to go...
Thank you for your help in advance.
I am trying to display 5 random images, each time I click a button.
The following is my HTML code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<meta charset = "UTF-8">
<title>Card Changer</title>
<?php
ini_set( 'display_errors', 1 );
error_reporting(E_ALL);
?>
</head>
<body>
<h1 align = 'center'>Card Changer</h1>
<form>
<table align = 'center'>
<tr>
<td><?php print "$array[$num_list[0]]"; ?></td>
<td><?php print "$array[$num_list[1]]"; ?></td>
<td><?php print "$array[$num_list[2]]"; ?></td>
<td><?php print "$array[$num_list[3]]"; ?></td>
<td><?php print "$array[$num_list[4]]"; ?></td>
</tr>
<tr><td align = 'center'><input type = 'button' value = 'Change' onclick = 'document.location = "cardChanger.php"' /></td></tr>
</table>
</form>
</body>
</html>
And the following is my PHP code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<meta charset="UTF-8">
<title>Poker Dealer</title>
</head>
<body>
<?php
ini_set( 'display_errors', 1 );
error_reporting(E_ALL);
$array = glob ("cards/*.gif"); //store paths in 'cards' directory with '.gif' extension
$max = count($array); //check how many contents has created in array
//pick five images from "cards" folder, no duplicate, randomly
$num_list = range(1,$max);
$num_list = array_rand($num_list,5);
shuffle ($num_list);
print "$array[$num_list[0]]"."<br>";
print "$array[$num_list[1]]"."<br>";
print "$array[$num_list[2]]"."<br>";
print "$array[$num_list[3]]"."<br>";
print "$array[$num_list[4]]"."<br>";
?>
</body>
</html>
As usual, my HTML code is not communicating to my PHP code and my HTML page is not displaying any images now.
How can I display the multiple images in HTML page using PHP and when I click a button, change the images, without displaying any duplicates? Is my approach going to a right direction...?
For this practice, I am using the images of a deck of playing cards and put them into a folder named "cards". I thought about that writing array for every single card, like "2c.gif", "2d.gif", "2h.gif", "2s.gif", and while I was searching online, I found a piece of code, which might be the way to go...
Thank you for your help in advance.
Why Experts Exchange?
Experts Exchange always has the answer, or at the least points me in the correct direction! It is like having another employee that is extremely experienced.
Jim Murphy
Programmer at Smart IT Solutions
When asked, what has been your best career decision?
Deciding to stick with EE.
Mohamed Asif
Technical Department Head
Being involved with EE helped me to grow personally and professionally.
Carl Webster
CTP, Sr Infrastructure Consultant
Ask ANY Question
Connect with Certified Experts to gain insight and support on specific technology challenges including:
- Troubleshooting
- Research
- Professional Opinions
Did You Know?
We've partnered with two important charities to provide clean water and computer science education to those who need it most. READ MORE