jagguy
asked on
tangent graph
Hi,
How do I do this question as I am stuck .
f(x)=(1/(2x-4)) + 3
If ( p, q) is any point on the graph of y = f (x), show that the equation of the tangent to y = f (x) at this point can be written as (2p – 4)2(y – 3) = –2x + 4p – 4.
How do I do this question as I am stuck .
f(x)=(1/(2x-4)) + 3
If ( p, q) is any point on the graph of y = f (x), show that the equation of the tangent to y = f (x) at this point can be written as (2p – 4)2(y – 3) = –2x + 4p – 4.
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
If you know those steps, what are you stuck on?
ASKER
getting the final answer I got stuck on
Did you get a different answer?
ASKER
ok I got it, as I did the normal and not tangent
ASKER