Delete values in last cell of rows based on values in other cells

Dear Experts:

My current document has hundreds of tables. I would like to perform the following task using VBA.

As soon as the macro hits the value '99-99' (The value '99-99' is always located in the first cell of any row) in any of the rows, the contents of the last cell in that row is to be deleted.

All of the tables in this document feature the exact same number of columns.

Help is much appreciated. Thank you very much in advance.

Regards, Andreas
Andreas HermleTeam leaderAsked:
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KimputerCommented:
Possibility for a sample document?
0
Chris BottomleySoftware Quality Lead EngineerCommented:
Andreas

I was concerned to avoid iterating on row as this would be inefficient so please try the following on a copy of your data:

Sub Q_28270411_1()
Dim tbl As Table
Dim cols As Integer
Dim intCol As Integer
Dim rng As Range
Dim subRange As Range


    Set rng = ActiveDocument.Range
    With rng.Find
        .ClearFormatting
        .Text = "99-99"
        Do While .Execute(Forward:=True) = True
            If rng.Information(wdWithInTable) Then
                Set subRange = ActiveDocument.Range(rng.Start, rng.End)
                subRange.Collapse Direction:=wdCollapseEnd
                If subRange.Cells(1).ColumnIndex = 1 Then
'                    Debug.Print rng.Tables(1).Rows(rng.Cells(1).RowIndex).Cells(rng.Tables(1).Columns.Count).Range.Text
                    rng.Tables(1).Rows(rng.Cells(1).RowIndex).Cells(rng.Tables(1).Columns.Count).Range.Text = ""
                End If
            End If
        Loop
    End With

End Sub

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Chris
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Andreas HermleTeam leaderAuthor Commented:
Hi Chis,

great job. Works like a charm. Saves me lots of time. Thank you very much for your swift and professional support.

Regards, Andreas
0
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