Generate Json using JS

Deal all,
The following code  generate json
var jsonfied = [{
		items : items.replace(/,$/, "").split("\n").map(function(item) {
                        var values = item.split(',');
			return {
				name : values[0],
                                column_type: values[1]

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to parse this data :

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I just need to change the js code to pares this data:

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and generate the following json:
      TableName: "TableName1" ,
      languages: [
      { name: "FieldNameID" , column_type:"typ1"  },
      { name: "FieldName02" , column_type:"typ2" },
      { name: "FieldName03" , column_type:"typ3"  },

      TableName: "TableName2" ,
      languages: [
      { name: "FieldNameID" , column_type:"typ4" },
      { name: "FieldName02" , column_type:"typ1" },
      { name: "FieldName03" , column_type:"typ2" },


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Alexandre SimõesManager / Technology SpecialistCommented:
Hi mate, here it is:
This time I didn't do it with the map because there's no way to properly split by the table name row.
So what I do is split by line and create a new item each time I find a line that ends with :

var items = 'Tablename1:\nFieldNameID,typ1\nFieldName02,typ2\nFieldName03,typ3\nTablename:\nFieldNameID,typ4\nFieldName02,typ1\nFieldName03,typ2';

var jsonfied = function(input) {
    var result = [];
    var lines = items.replace(/,$/, "").split("\n");
    var item = null;
    for (var i=0;i<lines.length;i++){
        if(lines[i].substr(-1) === ':'){
            if(item) result.push(item);
            item = { tableName: lines[i].split(':')[0], languages: [] };
        } else {
            var values = lines[i].split(',');
            item.languages.push({ name: values[0], column_type: values[1] });
    if(item) result.push(item);
    return result;

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ethar1Author Commented:
what is the useful of input here?
Alexandre SimõesManager / Technology SpecialistCommented:
I added it just to make the function independent of an external variable but then I ended up not using it, sorry.
Here's the sample without it:

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ethar1Author Commented:
ok, I just need to add [ and ] for whole result string ?
ethar1Author Commented:
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