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get distinct Dates from timestamp values

hi guys
I have  a MODIFY_DATE timestamp column with values like this
MODIFY_DATE
2013-10-18 10:54:02.270
2013-10-18 10:54:02.270
2013-10-22 06:30:35.373
2013-10-23 16:51:14.790
2013-10-23 16:51:14.790


I am trying to get the Distinct Date from the column, my resultset should look like this
2013-10-18
2013-10-22
2013-10-23

what i have is
select distinct cast(MODIFY_DATE AS Date) as Date from CUSTOMER_TABLE
 where  cast(MODIFY_DATE AS Date) = DATEADD(day, 0, convert(date, GETDATE()))
but this will get only todays date.

Any idea how i can acchieve this?

thanks
0
royjayd
Asked:
royjayd
  • 2
3 Solutions
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Worked for me without the WHERE clause..
CREATE TABLE #foo (MODIFY_DATE datetime) 

INSERT INTO #foo (MODIFY_DATE)
VALUES
	('2013-10-18 10:54:02.270'), 
	('2013-10-18 10:54:02.270'), 
	('2013-10-22 06:30:35.373'), 
	('2013-10-23 16:51:14.790'), 
	('2013-10-23 16:51:14.790')

select distinct cast(MODIFY_DATE AS Date) as Date 
from #foo

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0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>where  cast(MODIFY_DATE AS Date) = DATEADD(day, 0, convert(date, GETDATE()))
What were you trying to accomplish with the above statement?
DateAdd(day, 0, any date) will equal any date.
0
 
PortletPaulCommented:
no points please:

yep, all you need to do is remove the where clause

>> where  cast(MODIFY_DATE AS Date) = DATEADD(day, 0, convert(date, GETDATE()))
>> but this will get only todays date.
because that's what you just asked for :)

cast(MODIFY_DATE AS Date)  also could be: convert(date,Modify_date)
convert(date, GETDATE()) also could be: cast(getdate() AS Date)

so, your where clause could be rewritten as:

where cast(MODIFY_DATE AS Date)  = cast(getdate() AS Date)

i.e. only where that field = today
0
 
royjaydAuthor Commented:
thanks y'all
0

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