How to remove the junk values from csv file

Almost forget::
Once I remove this junk/signature values from csv file, I load them into tables using SSIS package. Thanks

use this command:

findstr /B  /V "Report Name Company"  filename.csv > fixedfile.csv

this command will output all lines not beginning with those search strings to the fixedfile.csv

Good Luck,

- gurutc

awesome I will try that now :)

GuruTc,
unfortunately it is not excluding these values, though it created new csv file.
Anything missing here?

"ReportName"
"Copyright (c) 2000-2013 , inc. All rights reserved."
"Confidential Information - Do Not Distribute"
"Generated By: XYZ  10/1/2013 12:35 PM"
"Name of the company"

This is something tried:
findstr /B  /V "ReportName Copyright Confidential Generated Name"  filename.csv > fixedfile.csv

but no luck

Are there any leading spaces before those strings in the file?

Another way is a multi step but could be put in a batch file:

findstr /V  /I  /C:"Report Generated by"  filename.csv > fixedfile1.csv
findstr /V  /I  /C:"Name of"  fixedfile1.csv > fixedfile2.csv
findstr /V  /I  /C:"Company Address"  fixedfile2.csv > fixedfile3.csv

This will remove the lines with these strings no matter if there are spaces or tabs or anything else before the strings.

- gurutc

Your try would work if you took out the /B which means beginning of line and add /I making it case-insensitive.

- gurutc

I think what you need is to have a list of first words from each line in the signature. Try:

findstr /B  /V "<first word from report name here> Copyright Confidential Generated <first word of the company name here>"  filename.csv > fixedfile.csv

So if the report name is:  Address List  and the company name is  ABC Inc.  then your command will be:

findstr /B  /V "Address Copyright Confidential Generated ABC"  filename.csv > fixedfile.csv

@gurutc
"ReportName"
"Copyright (c) 2000-2013 , inc. All rights reserved."
"Confidential Information - Do Not Distribute"
"Generated By: XYZ  10/1/2013 12:35 PM"
"Name of the company"
As you see here it has double quotations at beginning of the lines. Sorry i should have told you this before.

Thank you so much Guru.. this one has removed the values. Closing this out.

Hi @gurutc,

If am using /I /V it is excluding many valid records. Is there any other way to remove these double quotes of each column and use

findstr /B /V ..

I know this ticket has been closed. Do you want me to open a new ticket for this request?

setlocal enabledelayedexpansion
if exist after.csv del after.csv
for /f "delims=" %%A in (before.csv) do (
  set csvline=%%A
  echo !csvline:"=! >> after.csv
  )

Select allOpen in new window

I'm using this code to trim the double quotes.. but it is not working.

When I get back to my PC we"ll solve this

-gurutc

Hi,

Use the \ directive to escape the double quotes and treat it as literal:

findstr   /V   /B "\"ReportName \"Copyright \"Confidential \"Generated \"Name"  filename.csv > fixedfile.csv

You only have to escape the quotes that are at the beginning of each of your search terms so those quote marks also become part of what's being searched for.  

So only the lines starting with the following will be recognized and left out:

"ReportName
"Copyright
"Confidential
"Generated
"Name

If there's anything hidden before the " mark you'll have to remove the /B which means beginning of line, but let's count on our hoping there isn't and this'll work groovy.

- gurutc

Thank you so much again guru :)