=MID(A1;FIND(" ";A1)+5;LENGTH(A1) - FIND("-";A1;FIND("-";A1))-
=TEIL(A1;(FINDEN(" ";A1;1)+5);(FINDEN(" ";A1;(FINDEN(" ";A1;1)+5)))-(FINDEN(" ";A1;1)+5))
Regards
Function RegExpFindSubmatch(LookIn As String, PatternStr As String, Optional MatchPos, _
Optional SubmatchPos, Optional MatchCase As Boolean = True, _
Optional MultiLine As Boolean = False)
' Function written by Patrick G. Matthews. You may use and distribute this code freely,
' as long as you properly credit and attribute authorship and the URL of where you
' found the code
' This function relies on the VBScript version of Regular Expressions, and thus some of
' the functionality available in Perl and/or .Net may not be available. The full extent
' of what functionality will be available on any given computer is based on which version
' of the VBScript runtime is installed on that computer
' This function uses Regular Expressions to parse a string (LookIn), and return "submatches"
' from the various matches to a pattern (PatternStr). In RegExp, submatches within a pattern
' are defined by grouping portions of the pattern within parentheses.
' Use MatchPos to indicate which match you want:
' MatchPos omitted : function returns results for all matches
' MatchPos = 1 : the first match
' MatchPos = 2 : the second match
' MatchPos = <positive integer> : the Nth match
' MatchPos = 0 : the last match
' MatchPos = -1 : the last match
' MatchPos = -2 : the 2nd to last match
' MatchPos = <negative integer> : the Nth to last match
' Use SubmatchPos to indicate which match you want:
' SubmatchPos omitted : function returns results for all submatches
' SubmatchPos = 1 : the first submatch
' SubmatchPos = 2 : the second submatch
' SubmatchPos = <positive integer> : the Nth submatch
' SubmatchPos = 0 : the last submatch
' SubmatchPos = -1 : the last submatch
' SubmatchPos = -2 : the 2nd to last submatch
' SubmatchPos = <negative integer> : the Nth to last submatch
' The return type for this function depends on whether your choice for MatchPos is looking for
' a single value or for potentially many. All arrays returned by this function are zero-based.
' When the function returns a 2-D array, the first dimension is for the matches and the second
' dimension is for the submatches
' MatchPos omitted, SubmatchPos omitted: 2-D array of submatches for each match. First dimension
' based on number of matches (0 to N-1), second dimension
' based on number of submatches (0 to N-1)
' MatchPos omitted, SubmatchPos used : 2-D array (0 to N-1, 0 to 0) of the specified submatch
' from each match
' MatchPos used, SubmatchPos omitted : 2-D array (0 to 0, 0 to N-1) of the submatches from the
' specified match
' MatchPos used, SubmatchPos used : String with specified submatch from specified match
' For any submatch that is not found, the function treats the result as a zero-length string
' If MatchCase is omitted or True (default for RegExp) then the Pattern must match case (and
' thus you may have to use [a-zA-Z] instead of just [a-z] or [A-Z]).
' If you use this function in Excel, you can use range references for any of the arguments.
' If you use this in Excel and return the full array, make sure to set up the formula as an
' array formula. If you need the array formula to go down a column, use TRANSPOSE()
' Normally as an object variable I would set the RegX variable to Nothing; however, in cases
' where a large number of calls to this function are made, making RegX a static variable that
' preserves its state in between calls significantly improves performance
Static RegX As Object
Dim TheMatches As Object
Dim Mat As Object
Dim Answer() As String
Dim Counter As Long
Dim SubCounter As Long
' Evaluate MatchPos. If it is there, it must be numeric and converted to Long
If Not IsMissing(MatchPos) Then
If Not IsNumeric(MatchPos) Then
RegExpFindSubmatch = ""
Exit Function
Else
MatchPos = CLng(MatchPos)
End If
End If
' Evaluate SubmatchPos. If it is there, it must be numeric and converted to Long
If Not IsMissing(SubmatchPos) Then
If Not IsNumeric(SubmatchPos) Then
RegExpFindSubmatch = ""
Exit Function
Else
SubmatchPos = CLng(SubmatchPos)
End If
End If
' Create instance of RegExp object
If RegX Is Nothing Then Set RegX = CreateObject("VBScript.RegExp")
With RegX
.Pattern = PatternStr
.Global = True
.IgnoreCase = Not MatchCase
.MultiLine = MultiLine
End With
' Test to see if there are any matches
If RegX.Test(LookIn) Then
' Run RegExp to get the matches, which are returned as a zero-based collection
Set TheMatches = RegX.Execute(LookIn)
' If MatchPos is missing, user either wants array of all the submatches for each match, or an
' array of all the specified submatches for each match. Build it and assign it as the
' function's return value
If IsMissing(MatchPos) Then
' Return value is a 2-D array of all the submatches for each match
If IsMissing(SubmatchPos) Then
For Counter = 0 To TheMatches.Count - 1
Set Mat = TheMatches(Counter)
' To determine how many submatches there are we need to first evaluate a match. That
' is why we redim the array inside the for/next loop
If Counter = 0 Then
ReDim Answer(0 To TheMatches.Count - 1, 0 To Mat.Submatches.Count - 1) As String
End If
' Loop through the submatches and populate the array. If the Nth submatch is not
' found, RegExp returns a zero-length string
For SubCounter = 0 To UBound(Answer, 2)
Answer(Counter, SubCounter) = Mat.Submatches(SubCounter)
Next
Next
' Return value is a 2-D array of the specified submatch for each match.
Else
For Counter = 0 To TheMatches.Count - 1
Set Mat = TheMatches(Counter)
' To determine how many submatches there are we need to first evaluate a match. That
' is why we redim the array inside the for/next loop. If SubmatchPos = 0, then we want
' the last submatch. In that case reset SubmatchPos so it equals the submatch count.
' Negative number indicates Nth to last; convert that to applicable "positive" position
If Counter = 0 Then
ReDim Answer(0 To TheMatches.Count - 1, 0 To 0) As String
Select Case SubmatchPos
Case Is > 0: 'no adjustment needed
Case 0, -1: SubmatchPos = Mat.Submatches.Count
Case Is < -Mat.Submatches.Count: SubmatchPos = -SubmatchPos
Case Else: SubmatchPos = Mat.Submatches.Count + SubmatchPos + 1
End Select
End If
' Populate array with the submatch value. If the submatch value is not found, or if
' SubmatchPos > the count of submatches, populate with a zero-length string
If SubmatchPos <= Mat.Submatches.Count Then
Answer(Counter, 0) = Mat.Submatches(SubmatchPos - 1)
Else
Answer(Counter, 0) = ""
End If
Next
End If
RegExpFindSubmatch = Answer
' User wanted the info associated with the Nth match (or last match, if MatchPos = 0)
Else
' If MatchPos = 0 then make MatchPos equal the match count. If negative (indicates Nth
' to last), convert to equivalent position.
Select Case MatchPos
Case Is > 0: 'no adjustment needed
Case 0, -1: MatchPos = TheMatches.Count
Case Is < -TheMatches.Count: MatchPos = -MatchPos
Case Else: MatchPos = TheMatches.Count + MatchPos + 1
End Select
' As long as MatchPos does not exceed the match count, process the Nth match. If the
' match count is exceeded, return a zero-length string
If MatchPos <= TheMatches.Count Then
Set Mat = TheMatches(MatchPos - 1)
' User wants a 2-D array of all submatches for the specified match; populate array. If
' a particular submatch is not found, RegExp treats it as a zero-length string
If IsMissing(SubmatchPos) Then
ReDim Answer(0 To 0, 0 To Mat.Submatches.Count - 1)
For SubCounter = 0 To UBound(Answer, 2)
Answer(0, SubCounter) = Mat.Submatches(SubCounter)
Next
RegExpFindSubmatch = Answer
' User wants a single value
Else
' If SubmatchPos = 0 then make it equal count of submatches. If negative, this
' indicates Nth to last; convert to equivalent positive position
Select Case SubmatchPos
Case Is > 0: 'no adjustment needed
Case 0, -1: SubmatchPos = Mat.Submatches.Count
Case Is < -Mat.Submatches.Count: SubmatchPos = -SubmatchPos
Case Else: SubmatchPos = Mat.Submatches.Count + SubmatchPos + 1
End Select
' If SubmatchPos <= count of submatches, then get that submatch for the specified
' match. If the submatch value is not found, or if SubmathPos exceeds count of
' submatches, return a zero-length string. In testing, it appeared necessary to
' use CStr to coerce the return to be a zero-length string instead of zero
If SubmatchPos <= Mat.Submatches.Count Then
RegExpFindSubmatch = CStr(Mat.Submatches(SubmatchPos - 1))
Else
RegExpFindSubmatch = ""
End If
End If
Else
RegExpFindSubmatch = ""
End If
End If
' If there are no matches, return empty string
Else
RegExpFindSubmatch = ""
End If
Cleanup:
' Release object variables
Set Mat = Nothing
Set TheMatches = Nothing
End Function
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