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Help with creating string values based on another string values using VB.NET

Posted on 2013-11-03
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Last Modified: 2013-11-04
Hi,

I have string S with the following fixed values  S = BEL,CAN,FRA,DEU,USA

If I have string S1 = 0,2

How do I create a new string S2 = BEL,FRA?

The values in S  should relate to 0,1,2,4  where

BEL relates t0 0
CAN relates to 1
FRA relates to 3 etc...
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Question by:vcharles
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5 Comments
 
LVL 63

Accepted Solution

by:
Fernando Soto earned 300 total points
ID: 39620412
Hi vcharles;

This code snippet will give you what you want.

' Your initial string
Dim S As String = "BEL,CAN,FRA,DEU,USA"

' Convert the string S into a collection that you can index into
Dim S_Collection As List(Of String) = S.Split(New String() {",", " "}, StringSplitOptions.RemoveEmptyEntries).ToList()
' Convert the string S1 into a collection of integers so that it can be used to index into above collection
Dim S1 As String = "0,2"
Dim S1_Index_Collection As New List(Of Integer)
For Each i As String In S1
    If i = "," OrElse i = " " Then Continue For
    Dim idx As Integer = Integer.Parse(i)
    S1_Index_Collection.Add(idx)
Next

Dim S2 As String = ""
' Now you can get the values from S_Collection
For Each idx As Integer In S1_Index_Collection
    If S2.Length = 0 Then
        S2 = S_Collection(idx)
    Else
        S2 += "," & S_Collection(idx)
    End If
Next

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LVL 86

Assisted Solution

by:Mike Tomlinson
Mike Tomlinson earned 200 total points
ID: 39620423
Another one:
        Dim S As String = "BEL,CAN,FRA,DEU,USA"
        Dim S1 As String = "0,2"

        Dim countries() As String = S.Split(",")
        Dim codes() As Integer = Array.ConvertAll(S1.Split(","), Function(x) Int32.Parse(x))

        Dim output As New List(Of String)
        For Each code As Integer In codes
            output.Add(countries(code))
        Next

        Dim finalCountries As String = String.Join(",", output.ToArray)
        MessageBox.Show(finalCountries)

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Author Comment

by:vcharles
ID: 39620649
Thank You, will try them and get back to you.
0
 

Author Closing Comment

by:vcharles
ID: 39622245
Thank You.
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 39622326
Not a problem, glad to help.
0

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