Replace single quote with double when searching for name with apostrophe

That code will replace double quotes with nothing so not sure that's your problem
set @lastname = replace (LTRIM(RTRIM(@lastname)),'''', '')

What code are you using for the query/

I've saved the name as O'Brian (with the apostrophe). When searching for the name, I cant replace the apostrophe with blank. I need to replace it with single quotes in stored proc.

This is the where clause if I replace the single quotes with blank. I need to compare it with O'Brian not OBrian


where  opp.ACTIVE = 1   AND  opp.lastname LIKE 'OBrian%' AND  i.BusinessNameId  = 6

Hi,

does
where  opp.ACTIVE = 1   AND  opp.lastname LIKE 'O''Brian%' AND  i.BusinessNameId  = 6

work?

Regards
  David

Hi,

Look at the quotename function
http://technet.microsoft.com/en-us/library/ms176114.aspx

eg
use ExpertsExchange
go

declare @Parameter varchar( 256 )
set @Parameter = 'O''Brien'

select @Parameter

select quotename( @parameter, '''' )

Results

----------------------
O'Brien

(1 row(s) affected)


----------------------
'O''Brien'

(1 row(s) affected)

HTH
  David

That link you have is for sql 2012. I have sql 2008

I thought maybe this should work

where  opp.ACTIVE = 1   AND  replace (LTRIM(RTRIM(I.LastName)),'''', '') LIKE 'OBrian%' AND  i.BusinessNameId  = 6

but this didn't bring any rows either.

replace (LTRIM(RTRIM(I.LastName)),'''', '')  still bring O'Brian with apostrophe. That should replace it with blank so I could compare with with OBrian Correct?

let me see. This cant be that hard! will post back