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Update Previous Price for datatable

Posted on 2013-11-06
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Last Modified: 2013-11-13
I have a table
ModelID,
Code,
BusDate,
Price
PrevPrice


I need to update the PrevPrice by getting the Price value for a given ModelID, Code from the previous BusDate.

The tables primary key is ModelID, Code, BusDate

Example
ModelID, Code, BusDate ,     Price,   PrevPrice
1 ,            'ABX', 10/18/2013 ,  7.00  ,   0
1 ,            'ABX', 10/18/2013 ,  9.00  ,   0
1 ,            'ABX', 10/21/2013 ,  10.00 ,   0
1 ,            'ABX', 10/22/2013 ,  8.00  ,   0

In the above example I would the data after the update statement to be
1 ,            'ABX', 10/18/2013 ,  7.00  ,   0
1 ,            'ABX', 10/18/2013 ,  9.00  ,   7.00
1 ,            'ABX', 10/21/2013 ,  10.00 ,   9.00
1 ,            'ABX', 10/22/2013 ,  8.00  ,   10.00
0
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Question by:countrymeister
  • 3
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6 Comments
 
LVL 32

Expert Comment

by:awking00
ID: 39628104
Can we assume a time value is present for the busdate? Otherwise, how would you distinguish
1 ,            'ABX', 10/18/2013 ,  7.00  ,   0
1 ,            'ABX', 10/18/2013 ,  9.00  ,   7.00
from
1 ,            'ABX', 10/18/2013 ,  9.00  ,   0
1 ,            'ABX', 10/18/2013 ,  7.00  ,   9.00
?
0
 
LVL 1

Author Comment

by:countrymeister
ID: 39628115
Sorry, my example should have had the following, since ModelID, Code and BusDate are the primary key

ModelID, Code, BusDate ,     Price,   PrevPrice
1 ,            'ABX', 10/17/2013 ,  7.00  ,   0
1 ,            'ABX', 10/18/2013 ,  9.00  ,   0
1 ,            'ABX', 10/21/2013 ,  10.00 ,   0
1 ,            'ABX', 10/22/2013 ,  8.00  ,   0

In the above example I would the data after the update statement to be
1 ,            'ABX', 10/17/2013 ,  7.00  ,   0
1 ,            'ABX', 10/18/2013 ,  9.00  ,   7.00
1 ,            'ABX', 10/21/2013 ,  10.00 ,   9.00
1 ,            'ABX', 10/22/2013 ,  8.00  ,   10.00
0
 
LVL 32

Expert Comment

by:awking00
ID: 39628239
SQL> select * from yourtable;
   MODELID COD BUSDATE        PRICE  PREVPRICE
---------- --- --------- ---------- ----------
         1 ABX 17-OCT-13          7          0
         1 ABX 18-OCT-13          9          0
         1 ABX 21-OCT-13         10          0
         1 ABX 22-OCT-13          8          0

SQL> merge into yourtable y
  2  using
  3  (select modelid, code, busdate, price,
  4   lag(price) over (partition by modelid, code order by busdate) prevprice
  5   from yourtable) x
  6  on (y.modelid = x.modelid and y.code = x.code and y.busdate = x.busdate)
  7  when matched then
  8  update set y.prevprice = nvl(x.prevprice,0);

4 rows merged.
SQL> select * from yourtable;
   MODELID COD BUSDATE        PRICE  PREVPRICE
---------- --- --------- ---------- ----------
         1 ABX 17-OCT-13          7          0
         1 ABX 18-OCT-13          9          7
         1 ABX 21-OCT-13         10          9
         1 ABX 22-OCT-13          8         10
0
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LVL 1

Author Comment

by:countrymeister
ID: 39628331
I cannot use lag as it is a 2012 function. I am using sql 2008
0
 
LVL 32

Accepted Solution

by:
awking00 earned 1600 total points
ID: 39628447
Try this -
merge into yourtable a
using
(select x.modelid, x.code, x.busdate, x.price, nvl(y.price,0) as prevprice from
 (select modelid, code, busdate, price,
  row_number() over (partition by modelid, code order by busdate) rn
  from yourtable) x left join
 (select modelid, code, busdate, price,
  row_number() over (partition by modelid, code order by busdate) rn
  from yourtable) y
 on y.rn = x.rn - 1) z
on (a.modelid = z.modelid and a.code = z.code and a.busdate = z.busdate)
when matched then
update set prevprice = z.prevprice;
0
 
LVL 41

Assisted Solution

by:Sharath
Sharath earned 400 total points
ID: 39638028
You can try like this.
;with cte as (
  select *,row_number() over (partition by ModelID,Code order by BusDate) rn
    from test)
update c1
   set c1.PrevPrice = coalesce(c2.Price,0)
  from cte c1
  left join cte c2 on c1.rn = c2.rn + 1

Open in new window


check this. http://sqlfiddle.com/#!3/785590/13
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