• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 327
  • Last Modified:

mvc, view, asp.net

<form
                                         method="post"
                                         action="/xxx?inputState=@inputState&inputBond=@inputBond"  
                                         enctype="multipart/form-data"
                                         >

How to convert above to @html.begin()?
in razor/c#/asp.net/mvc
0
solution1368
Asked:
solution1368
1 Solution
 
StephanLead Software EngineerCommented:
How is your route for the form action?
/xxx?inputState=@inputState&inputBond=@inputBond

Open in new window

0
 
Ioannis ParaskevopoulosCommented:
@using (Html.BeginForm("YourActionName", "YourControllerName", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    <fieldset>
        @Html.EditorFor(m => m.Phone)
        @Html.EditorFor(m => m.SSN)
        <input type="submit" value="Submit" />
    </fieldset>
}

Open in new window


Just replace YourActionName and YourControllerName with the appropriate values.

Giannis
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now