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XSL: use contains to filter variable further

Posted on 2013-11-07
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Last Modified: 2013-11-07
i have the following variable within a function which finds 2 matching records

<xsl:variable name="test"      select="
 //Itin/ServInfo/Serv[@Code='ED' and @Type= 'RED'][Name/@Number =$Id]/Text"/>

 I want to filter even further by matching against a value within Text.
So my function would receive this param as $DocNum

<Text>AS KK1 06L18MAR/CHAIR/ACCPT/USD2000/100RC CCVIXXXXXXXXXXXX0001EXPXXXX 8312312270746</Text>

The $DocNum I would be filtering against is the last number included in this string. (8312312270746)

so that then variable "test" would return that entire text bc it found matching DocNum as well.
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Question by:badtz7229
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7 Comments
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 39630616
XSLT2 solution

<xsl:variable name="test"      select="
 //Itin/ServInfo/Serv[@Code='ED' and @Type= 'RED'][Name/@Number =$Id][ends-with(Text, $DocNum)]/Text"/>

XSLT1 Solution

<xsl:variable name="test"      select="
 //Itin/ServInfo/Serv[@Code='ED' and @Type= 'RED'][Name/@Number =$Id][substring(Text, string-length(Text) - string-length($DocNum) + 1 , string-length($DocNum))]/Text"/>
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Author Comment

by:badtz7229
ID: 39630655
I used the XSLT21 solution and this returned two instances of <text>. It did not filter by DocNum
is there a way to use the "contains" function to filter?
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Accepted Solution

by:
Geert Bormans earned 2000 total points
ID: 39630707
is $DocNum equal to the number, or equal to the number in brackes?
In the latter case you need to filter the brackets first

I assumed it was important that the numbered string was at the end

Try
<xsl:variable name="test"      select="
 //Itin/ServInfo/Serv[@Code='ED' and @Type= 'RED'][Name/@Number =$Id][contains(Text, $DocNum)]/Text"/>

If Serv having the correct Text has two Text nodes, you will get them both
Use this instead then

<xsl:variable name="test"      select="
 //Itin/ServInfo/Serv[@Code='ED' and @Type= 'RED'][Name/@Number =$Id]/Text[contains(., $DocNum)]"/>
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Author Comment

by:badtz7229
ID: 39630711
sorry, no bracket. DocNum is equal to 8312312270746
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Expert Comment

by:Geert Bormans
ID: 39630717
then the above should work
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Author Closing Comment

by:badtz7229
ID: 39630746
thanks both worked.
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LVL 60

Expert Comment

by:Geert Bormans
ID: 39630754
welcome
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