Solved

SQL statement

Posted on 2013-11-07
6
318 Views
Last Modified: 2013-11-14
What is a SQL statement that will calculate age using the current date and the birth date?
0
Comment
Question by:pstre
6 Comments
 
LVL 29

Assisted Solution

by:Paul Jackson
Paul Jackson earned 125 total points
ID: 39632550
A good article on calculating age using tsql in the following link :

http://www.wiseowl.co.uk/blog/s216/calculating_age_in_sql_server.htm
0
 
LVL 48

Assisted Solution

by:PortletPaul
PortletPaul earned 375 total points
ID: 39632663
This case expression will give you age in years (assuming that's what you want)
SELECT
            UserID
          , YEAR(getdate()) - YEAR(BirthDate)
            - ( CASE
                   WHEN MONTH(BirthDate) > MONTH(getdate())
                     OR ( MONTH(BirthDate) = MONTH(getdate())
                        AND DAY(BirthDate) > DAY(getdate())
                        )
                   THEN 1
                   ELSE 0
                 END ) AS AgeReg
    FROM Users

Open in new window

0
 
LVL 1

Expert Comment

by:mkgtvm
ID: 39632890
select datediff (YY, '1983-03-23', getdate()) as YEAR -- in years

select datediff (MM, '1983-03-23', getdate()) as MONTHS -- in months

select datediff (DD, '1983-03-23', getdate()) as DATES -- in dates
0
Do You Know the 4 Main Threat Actor Types?

Do you know the main threat actor types? Most attackers fall into one of four categories, each with their own favored tactics, techniques, and procedures.

 
LVL 48

Assisted Solution

by:PortletPaul
PortletPaul earned 375 total points
ID: 39632962
datediff(years...) is not accurate

try

select datediff (YY, '1983-03-08', '2013-11-23')
union all
select datediff (YY, '1983-12-08', '2013-11-23')
union all
select
YEAR('2013-11-23') - YEAR('1983-12-08')
            - ( CASE
                   WHEN MONTH('1983-12-08') > MONTH('2013-11-23')
                     OR ( MONTH('1983-12-08') = MONTH('2013-11-23')
                        AND DAY('1983-12-08') > DAY('2013-11-23')
                        )
                   THEN 1
                   ELSE 0
                 END )

results:
30
30
29

29 is the correct age in years for '1983-12-08' / '2013-11-23'

If the month/day of "today" are earlier than the month/day of the birthdate then 1 needs to be deducted.
0
 

Author Comment

by:pstre
ID: 39635955
Wow...lots of different answers.  There are 1300 employees where HR needs the age as of 12/31/2013.  I will need to add another column that is "Age as of 12/31/2013.  Having the Birthdate, how can I update the SQL statement below to reflect the age as of 12/31/2013?

select LASTNAME, FRSTNAME, BRTHDATE, DIVISIONCODE_I, DEPRTMNT
from UPR00100
where EMPLCLAS <> 'terminated'
order by EMPLCLAS


Hortin                     Janet                1951-07-15 00:00:00.000      001005       001    
Sparks                     Matthew              1976-08-12 00:00:00.000      001008       001    
Gammon                     Patricia             1952-08-29 00:00:00.000      003502       003    
Porter                     Laura                1967-10-12 00:00:00.000      003001       002    
Vaughn                     John                 1971-03-22 00:00:00.000      092002       092    
Acheson                    Shawn                1966-03-14 00:00:00.000      003001       002    
Tsalik                     Ephraim              1977-02-02 00:00:00.000      001007       001
0
 
LVL 48

Accepted Solution

by:
PortletPaul earned 375 total points
ID: 39636374
If your evaluation points are always 31st of December, then the simple year-year approach will work, the case expression approach will also work for that date or any other. I would still recommend the case expression.
DECLARE @d AS datetime = '2013-12-31'

SELECT
        lastname
      , frstname
      , divisioncode_i
      , deprtmnt
      , convert(varchar(10),brthdate,121) AS brthdate
      , YEAR(@d) - YEAR(brthdate)
            - ( CASE
                   WHEN MONTH(brthdate) > MONTH(@d)
                     OR ( MONTH(brthdate) = MONTH(@d)
                        AND DAY(brthdate) > DAY(@d)
                        )
                   THEN 1
                   ELSE 0
                 END ) AS Age_by_case

      , YEAR(@d) - YEAR(brthdate) AS "Age by year - year"
FROM  UPR00100
;

Open in new window

0

Featured Post

What Should I Do With This Threat Intelligence?

Are you wondering if you actually need threat intelligence? The answer is yes. We explain the basics for creating useful threat intelligence.

Join & Write a Comment

Suggested Solutions

Let's review the features of new SQL Server 2012 (Denali CTP3). It listed as below: PERCENT_RANK(): PERCENT_RANK() function will returns the percentage value of rank of the values among its group. PERCENT_RANK() function value always in be…
Load balancing is the method of dividing the total amount of work performed by one computer between two or more computers. Its aim is to get more work done in the same amount of time, ensuring that all the users get served faster.
Via a live example, show how to extract insert data into a SQL Server database table using the Import/Export option and Bulk Insert.
This is Part 3 in a 3-part series on Experts Exchange to discuss error handling in VBA code written for Excel. Part 1 of this series discussed basic error handling code using VBA. http://www.experts-exchange.com/videos/1478/Excel-Error-Handlin…

757 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

20 Experts available now in Live!

Get 1:1 Help Now