Get value without quotes using curl and sed

This does what I want except I do not want the quotations at the beginning and end:
curl -sk 'https://zuhqtr5.couchappy.com/site/www/' | sed -e 's/[{}]/''/g' | awk -v RS=',"' -F: '/^_rev/ {print $2}'

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How can I get the same results without the quotes?
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hankknightAsked:
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simon3270Connect With a Mentor Commented:
If you want all quotes removed from the string, add:
    | tr -d "'"'"'
to the end of the command - that deletes all double and single quotes
(it's double single double single double single)
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