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Linux Shell Scripting: Trim last slash

Posted on 2013-11-08
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Last Modified: 2013-11-10
In both of these cases, I want "http://example.com" to be returned.

If there is a slash on the end it should be trimmed.

u="http://example.com/xyz"
x=${u%/*}
echo $x
u="http://example.com/xyz/"
x=${u%/*}
echo $x

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Question by:hankknight
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by:woolmilkporc
ID: 39634567
u="http://example.com"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
u="http://example.com/xyz"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
u="http://example.com/xyz/"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
u="http://example.com/abc/def/xyz"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
u="http://example.com/abc/def/xyz/"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
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Author Comment

by:hankknight
ID: 39634575
In these examples I would want:
http://example.com/abc/def/xyz


I only want the trailing slash to be trimmed.


u="http://example.com/abc/def/xyz"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
u="http://example.com/abc/def/xyz/"
x=$(echo $u |awk -F"/|//" '{print $1 "//" $2}')
echo $x
0
 
LVL 68

Assisted Solution

by:woolmilkporc
woolmilkporc earned 200 total points
ID: 39634608
"I only want the trailing slash to be trimmed."

and

"In both of these cases, I want "http://example.com" to be returned."

Strange contradiction. Anyway:

u="http://example.com/"
x=$(echo $u | sed 's/\/$//')
echo $x
u="http://example.com"
x=$(echo $u | sed 's/\/$//')
echo $x
u="http://example.com/xyz"
x=$(echo $u | sed 's/\/$//')
echo $x
u="http://example.com/xyz/"
x=$(echo $u | sed 's/\/$//')
echo $x
u="http://example.com/abc/def/xyz/"
x=$(echo $u | sed 's/\/$//')
echo $x
u="http://example.com/abc/def/xyz"
x=$(echo $u | sed 's/\/$//')
echo $x

To  clarify:

s/\/$//

is

"s" "slash" "backslash" "slash" "dollar" "slash" "slash"
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LVL 84

Accepted Solution

by:
ozo earned 300 total points
ID: 39635082
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