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mapping bytes to an array of structs

LuckyLucks
LuckyLucks asked
on
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Last Modified: 2013-11-22
I have a struct defined like so:
struct A{
  int a;
  float b;

};

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I have void * pointer to bytes of memory being returned by a function. I would like to map the bytes to an array of struct (my struct A) so that I can later loop through and print out the values.

I tried this:
struct A *download=(struct A*) malloc(sizeof(A)*numElements);
download=(struct A*) ft_returning_bytes();
if(download!=(struct A*)NULL{
   for(int k=0;k<numElements;k++){
        printf("%d %0.2f",download[k].a,dowload[k].b);
  }
}

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it prints incorrect values which i am not expecting. How  can this be done in c++?
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Commented:
ft_returning_bytes is glMapBuffer , a function that retruns from gpu.

"glMapBuffer maps to the client's address space the entire data store of the buffer object
            currently bound to target. The data can then be directly read and/or written relative to
            the returned pointer, depending on the specified access policy."

The data being returned is a contigous memory containing int,float,int,float,.....

I didn't want to create a struct for each int , float pair just to print it out. Is there an elegant way to print out the int,float pair without recreating a struct for every pair?

struct A *download;
download=(struct A*) ft_returning_bytes();
if(download!=(struct A*)NULL{
   for(int k=0;k<numElements;k++){
        printf("%d %0.2f",download[k].a,dowload[k].b);
  }
}

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Commented:
Without seeing the code for ft_returning_bytes the latest code snippet you posted is correct.

Here is some code that illustrates the concept. As you can see the loop to dump the struct is the same as the code you have posted. If your code is not working we need to know more about ft_returning_bytes
// 28290116.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"

struct A{
  int a;
  float b;

};

void * getBytes()
{
	struct A * pData = (struct A *)malloc(sizeof(struct A) * 10);
	int i;
	for(i=0;i<10;i++) {
		pData[i].a = i;
		pData[i].b = (float)(i*i/123.0);
	}
	return pData;
}

int _tmain(int argc, _TCHAR* argv[])
{
	struct A * pRet = (struct A *)getBytes();
	int i;

	if (pRet) {
		for (i=0;i<10;i++) {
			printf("I: %d = %d, A.a = %d, A.b = %f\n", i, pRet[i].a, pRet[i].b);
		}
	}

	return 0;
}

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Commented:
glMapBuffer uses GLfloat and not 'float'. a 'float' in c/c++ normally I 32-bit while a GLfloat could be 64-bit (what is double in c++).

I don't have seen code where a glMapBuffer points to a pair of int and float. instead I saw code like

GLfloat * data = (GLfloat*) glMapBuffer(GL_ARRAY_BUFFER, GL_READ_WRITE);

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what lets me think that a glMapBuffer normally is a GLfloat array. can you post a hex output of the data in memory?

but even if it is really a pair, you should use types GLint and GLfloat for types and should make sure that the c structure is "packed" what means that the compiler didn't add some space between the integer and the float for to get the members properly aligned - say at 8-byte boundaries. the packing can be added as compiler option (depending on your compiler or ide).

Sara

Author

Commented:
GLfloat array  - GLfloat is just
typedef float GLfloat;


 can you post a hex output of the data in memory? - how can i do this in VS C++?

Also,how can i verify things aren't being packed? Where should i be looking?
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I also want to award some pts to "by: sarabandePosted on 2013-11-11 at 07:46:30ID: 39638561" .

The memory chunk returned is being padded by an extra 8 bytes per row of what i was expecting.
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>> I also want to award some pts to ...
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