Solved

mySQL query help sum zero

Posted on 2013-11-12
3
661 Views
Last Modified: 2013-11-12
I have 3 tables:

TABLE-A - groups
GID     Group Name
-----     ------
1          GROUPA
2          GROUPB
3          GROUPC


TABLE-B - questions
QID     Question
-----    --------
1         How do you feel? (Scale 1-10)
2         How old are you? (Scale 1-10)
3        1 + 1? (Scale 1-10)

TABLE-C - questionResponses
RID     QID      GID       Result
-----    --------    --------    --------
1         1            1            2  -
2         1            2            5  -
3         2            3            6
4         3            1            1  -
5         2            1            9  -


I want result like this
QUERY OUTPUT

QID      GID       SUM
--------    --------    --------
1            1            2
2            1            9
3            1            1
1            2            5
2            2            0
3            2            0
1            3            0
2            3            6
3            3            0




This is as far as I have got:
SELECT Q.questionID, G.groupID, COALESCE(SUM(R.questionResponse),0)
FROM questions Q

LEFT JOIN questionResponses R
ON Q.questionID = R.questionID

LEFT JOIN groups G
ON G.groupID = R.groupID

WHERE Q.questionID IN ( 244,245,246 )

GROUP BY Q.questionID, G.groupID

ORDER BY Q.questionID

Open in new window

and the output looks like this:
query output
As you can see I am getting the sum for all 3 questions but it isnt including all 3 groups (should be 9).

Any help?
0
Comment
Question by:sjtinsley83
  • 2
3 Comments
 
LVL 32

Accepted Solution

by:
awking00 earned 500 total points
ID: 39641540
select x.qid, x.gid, sum(nvl(r.result,0)) results
from responses r
right join
(select q.qid, g.gid
 from questions q, groups g) x
on r.qid = x.qid and r.gid = x.gid
group by x.gid, x.qid
order by x.gid, x.qid;
0
 

Author Closing Comment

by:sjtinsley83
ID: 39641661
Thats brilliant! Think I need to read up on my right joins!
Thanks!
0
 
LVL 32

Expert Comment

by:awking00
ID: 39641778
Thanks. Could have used a left join, too. :-)
select x.qid, x.gid, sum(nvl(r.result,0)) results from
(select q.qid, g.gid
 from questions q, groups g) x
left join
responses r
on r.qid = x.qid and r.gid = x.gid
group by x.gid, x.qid
order by x.gid, x.qid;
0

Featured Post

3 Use Cases for Connected Systems

Our Dev teams are like yours. They’re continually cranking out code for new features/bugs fixes, testing, deploying, testing some more, responding to production monitoring events and more. It’s complex. So, we thought you’d like to see what’s working for us.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Many companies are looking to get out of the datacenter business and to services like Microsoft Azure to provide Infrastructure as a Service (IaaS) solutions for legacy client server workloads, rather than continuing to make capital investments in h…
These days, all we hear about hacktivists took down so and so websites and retrieved thousands of user’s data. One of the techniques to get unauthorized access to database is by performing SQL injection. This article is quite lengthy which gives bas…
Video by: Steve
Using examples as well as descriptions, step through each of the common simple join types, explaining differences in syntax, differences in expected outputs and showing how the queries run along with the actual outputs based upon a simple set of dem…
Polish reports in Access so they look terrific. Take yourself to another level. Equations, Back Color, Alternate Back Color. Write easy VBA Code. Tighten space to use less pages. Launch report from a menu, considering criteria only when it is filled…

911 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

21 Experts available now in Live!

Get 1:1 Help Now