Aligning graphics top left in the target cell after rotation using VBA

Try this modification

Sub InsertPictures()
'
' by Rgonzo, EE
'
Dim c As Range
Dim Image As Picture
'
For Each c In Range(Range("C2"), Range("C" & Rows.Count).End(xlUp))
    c.Offset(0, 1).Activate
    Set Image = ActiveSheet.Pictures.Insert(c.Value2)
    Imtop=image.top
    Imleft=image.left
   
        If Image.Height > Image.Width Then
           Image.ShapeRange.Rotation = 90
   
        If Image.Height > Application.CentimetersToPoints(4) Then
        Image.Height = Application.CentimetersToPoints(4)
       
        End If
       
        End If
     image.top=Imtop
     image.left=Imleft
Next
End Sub

Hi Rgonzo,

thank you very much for your quick and professional help.

Although this looks very logical to me, it actually does not do anything.

Any idea why ?

A quick search on the internet on a similar subject produced a code snippet that -at least- repositioned the graphics to various degrees to the right (still with the top alignment)

Image.ShapeRange.IncrementLeft Image.ShapeRange.Height / 2 - Image.ShapeRange.Width / 2
           Image.ShapeRange.IncrementTop Image.ShapeRange.Width / 2 - Image.ShapeRange.Height / 2

Regards, Andreas

When you select one of the rotated images, does the top left of the selection appear over the top left of the cell?

Hi rorya:

Thank you very much for your quick help:

Assuming running the following macro ID: 39643888

the ones that get rotated are not top aligned anymore but almost centered vertically.

The Horizontal Position is as follows: part of the image (to varying degrees) reach into Column C with most of picture being located in Column D.

See graphic.


Regards, Andreas

Can you upload a small sample for testing?

Hi,

pls try

Sub InsertPictures()
'
' by Rgonzo, EE
'
Dim c As Range
Dim Image As Picture
'
For Each c In Range(Range("C2"), Range("C" & Rows.Count).End(xlUp))
    c.Offset(0, 1).Activate
    Set Image = ActiveSheet.Pictures.Insert(c.Value2)
    
        If Image.Height > Image.Width Then
            If Image.Width > Application.CentimetersToPoints(4) Then
                Image.Width = Application.CentimetersToPoints(4)
            End If
            
            Image.ShapeRange.Rotation = 90
            Image.ShapeRange.IncrementTop -(Image.Height - Image.Width) / 2
            Image.ShapeRange.IncrementLeft (Image.Height - Image.Width) / 2
        Else
            If Image.Height > Application.CentimetersToPoints(4) Then
                Image.Height = Application.CentimetersToPoints(4)
            End If
        End If     
Next
End Sub 

Select allOpen in new window

Regards

I will not have time to do thorough testing right away.

I will do some testing tomorrow.

Thank you very much for your overwhelming and professional support.

Regards, Andreas

Dear both,

thank you very much  for your great and professional support. Both codes work just fine.

I am truly impressed with your coding abilities.

I hope you two find it fair if I split the points.  

300 go to Rory since he was a bit quicker to answer and
200 go to Rgonzo since he provided the base parts of this code.

Again, thank you very much for your great help.

Regards, Andreas

Dear Rgonzo and rorya:

I was gonna award points when I realized there is another requirement that needs to be considered:

Is it possible to adjust the rows so that they match the size of the graphics in Column D. As you know the size of the graphics can vary wildly from 1 to 4 cm.

I could also post this question as a new post.

Regards, Andreas

Hi Rgonzo,

I have tested it on around 50 Excel Records, works great so far. I will do some more testing and then let you know. Thank you very much for your superb help.

Regards, Andreas

Thank you very much for your great and professional support.

I really appreciate it. I am so glad I can turn to this forum for real professional help.

Regards, Andreas