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generate 'Create Table' script

In Microsoft  SSMS, we can right click on a table and through the menu, we can create a script to 'Create' the table.

Can this done outside of ssms using sqlcmd or some other means?
2 Solutions
Rajkumar GsSoftware EngineerCommented:
I think there is no simple query to build the create table script. But is possible by querying the system tables which would be heavy

You may refer the samples at

Big MontySenior Web Developer / CEO of ExchangeTree.org Commented:
try this script:

declare @table varchar(100)
set @table = 'MyTable' -- set table name here
declare @sql table(s varchar(1000), id int identity)

-- create statement
insert into  @sql(s) values ('create table [' + @table + '] (')

-- column list
insert into @sql(s)
    '  ['+column_name+'] ' + 
    data_type + coalesce('('+cast(character_maximum_length as varchar)+')','') + ' ' +
    case when exists ( 
        select id from syscolumns
        where object_name(id)=@table
        and name=column_name
        and columnproperty(id,name,'IsIdentity') = 1 
    ) then
        'IDENTITY(' + 
        cast(ident_seed(@table) as varchar) + ',' + 
        cast(ident_incr(@table) as varchar) + ')'
    else ''
    end + ' ' +
    ( case when IS_NULLABLE = 'No' then 'NOT ' else '' end ) + 'NULL ' + 
    coalesce('DEFAULT '+COLUMN_DEFAULT,'') + ','

 from information_schema.columns where table_name = @table
 order by ordinal_position

-- primary key
declare @pkname varchar(100)
select @pkname = constraint_name from information_schema.table_constraints
where table_name = @table and constraint_type='PRIMARY KEY'

if ( @pkname is not null ) begin
    insert into @sql(s) values('  PRIMARY KEY (')
    insert into @sql(s)
    	select '   ['+COLUMN_NAME+'],' from information_schema.key_column_usage
    	where constraint_name = @pkname
    	order by ordinal_position
    -- remove trailing comma
    update @sql set s=left(s,len(s)-1) where id=@@identity
    insert into @sql(s) values ('  )')
else begin
    -- remove trailing comma
    update @sql set s=left(s,len(s)-1) where id=@@identity

-- closing bracket
insert into @sql(s) values( ')' )

-- result!
select s from @sql order by id

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tommym121Author Commented:
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