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warning: [unchecked] unchecked cast

Posted on 2013-11-14
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Last Modified: 2013-11-14
Hi,

I get this compile error when I try to compile my class with -Xlint:unchecked

warning: [unchecked] unchecked cast
		E[] newData = (E[]) new Object[capacity];
		                    ^
  required: E[]
  found:    Object[]
  where E is a type-variable:
    E extends Object declared in class ArrayList

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If I compile without -Xlint, I get a warning, but no error, and the program works.

But it makes me nervous. Is there some way to 'fix' this to make -Xlint happy?

Thanks.
0
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Question by:Kyle Hamilton
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8 Comments
 
LVL 27

Expert Comment

by:dpearson
ID: 39648768
Have you tried:

E[] newData = new E[capacity] ;

Doug
0
 
LVL 25

Author Comment

by:Kyle Hamilton
ID: 39648792
so, putting this in front of the constructor was supposed to eliminate this message, but it had no effect on the message I'm getting in the console:

@SuppressWarnings("unchecked")

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I still get this message:

Note: ArrayList.java uses unchecked or unsafe operations.
Note: Recompile with -Xlint:unchecked for details.

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oh well, apparently this is not a big deal. If anyone has any input, I would appreciate it.

Thanks.
0
 
LVL 25

Author Comment

by:Kyle Hamilton
ID: 39648801
Hi Doug,

according to the book,
E[] newData = new E[capacity] ;

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would give ma an "invalid generic type" and won't compile.
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LVL 27

Expert Comment

by:dpearson
ID: 39648851
Ah - didn't know it was generic.

That's certainly harder.  If you have access to the class itself you can do:

E createObject(Class<E> clazz)
{
      return clazz.newInstance();
}

To create a typesafe instance of the class.  (If we can get that working, then need to figure out how to extend it to the whole array).

But to do that you need to pass in E.class at the time of the call to the generic method/class - can't look it up later on inside the method because E will have had its type erased.

Is that an option?

Doug
0
 
LVL 25

Author Comment

by:Kyle Hamilton
ID: 39648934
Ok, so I have this in my class:

private E createObject(Class<E> clazz) throws Exception{
		return clazz.newInstance();
	}

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and now this:

E newData = new E[capacity];

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now the error is:

error: generic array creation
		E newData = new E[capacity];

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Would it be helpful if I posted the whole class code?
0
 
LVL 27

Accepted Solution

by:
dpearson earned 500 total points
ID: 39648973
OK - it looks like the one you really want is
java.lang.reflect.Array.newInstance()

which allows you to create a new array of objects of a specific type, like E.class.

More docs on it here:
http://docs.oracle.com/javase/7/docs/api/java/lang/reflect/Array.html#newInstance(java.lang.Class, int)

And a bit of tutorial on the whole thing here:
http://docs.oracle.com/javase/tutorial/reflect/special/arrayInstance.html

Although I'm not sure this will ultimately clear the warning - as it seems
java.lang.reflect.Array.newInstance()
returns type Object
instead of type E[]
...

which looks wrong to me :)

Doug
0
 
LVL 25

Author Closing Comment

by:Kyle Hamilton
ID: 39649010
Thank you. much appreciated.

I better get outta this rabbit hole, for now.

Once I pass Level 1, I'll revisit this :) I think for now, I'm gonna live with the warning.

Cheers,
Koza
0
 
LVL 27

Expert Comment

by:dpearson
ID: 39649168
Haha - fair enough :)

Doug
0

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