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SQL Syntax

Posted on 2013-11-14
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Last Modified: 2013-11-20
I have two tables

Table1
ReturnType  varchar(10)
ReturnValue decimal

Table stores values such as (Daily, Weekly, Monthly) in the Return type column
and various return values


Table2
RangeType varchar(10)
RangeValue  0.1, 0.2. 0.5

Table 2 has RangeType which also stores values such as (Daily, Weekly, Monthly
 example
Daily  0.5  ( which means greater than 0.5
Daily  0.10  ( greater than 0.10)
Daily  0.20  ( greater than 0.2)

I need to join these two tables and generate a new column where based on the value in ReturnValue I assign it to a buket that falls in the RangeValue

Example

ReturnType, ReturnValue,  Range
Daily               0.21               > than 0.20
Daily               0.60               > than 0.50
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Comment
Question by:countrymeister
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10 Comments
 
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Expert Comment

by:chaau
Comment Utility
I think this should work. I have not tested it.
Select t1.ReturnType, t1.ReturnValue,  
MIN(t2.RangeValue) OVER (PARTITION BY t2.RangeType ORDER BY t2.RangeValue) AS Range
FROM Table1 t1 INNER JOIN Table2 t2 ON t1.ReturnType = t2.RangeType 

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Author Comment

by:countrymeister
Comment Utility
This does not work
0
 
LVL 24

Expert Comment

by:chaau
Comment Utility
Sorry, made a mistake. This is what happens when you post an untested solution.
Here, this should work:
Select t1.ReturnType, t1.ReturnValue,  
MAX(t2.RangeValue) AS Range
FROM Table1 t1 LEFT JOIN Table2 t2 
ON t1.ReturnType = t2.RangeType and t1.ReturnValue > t2.RangeValue
GROUP BY t1.ReturnType, t1.ReturnValue

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Author Comment

by:countrymeister
Comment Utility
chauu

I need the min value of ReturnValue greater than the RangeValue
Example Table 2 has the following values for Daily

0.1
0.2
0.5

Tthen if table 1 has Daily , and the Range Value = 0.15

This should give me 0.2 from Table 2
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Expert Comment

by:awking00
Comment Utility
How do want equal values to be handled? For example, if table1 has Daily and a Range Value of .10, does it belong with .1 or .2 of table2?
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LVL 31

Expert Comment

by:awking00
Comment Utility
Some more sample data for the two tables (e.g. include weekly and monthly and their respective ranges) plus your expected results would help a lot.
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Accepted Solution

by:
chaau earned 250 total points
Comment Utility
You are right. Please use this:
Select t1.ReturnType, t1.ReturnValue,  
MIN(t2.RangeValue) AS Range
FROM Table1 t1 LEFT JOIN Table2 t2 
ON t1.ReturnType = t2.RangeType and t1.ReturnValue < t2.RangeValue
GROUP BY t1.ReturnType, t1.ReturnValue 

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Author Comment

by:countrymeister
Comment Utility
by: awking00
here is some data, for every row in Table1 I need to assign a single range value
The final resulkt set should have
ID      ReturnType      ReturnValue , RangeValue

Table 1
ID      ReturnType      ReturnValue
226568      Daily      -0.02813024
226570      Daily      0.00406007
226572      Daily      -0.01723199
226573      Daily      0.02970666
226575      Daily      -0.03828653
226577      Daily      0.01418188
226579      Daily      -0.06490917
226580      Daily      0.00652104
226582      Daily      0.00661904
226584      Daily      0.11295950


Table2

ID      RangeType      RangeValue
1      Daily      -0.50000000
2      Daily      -0.25000000
3      Daily      -0.10000000
4      Daily      -0.05000000
5      Daily      0.00000000
6      Daily      0.05000000
7      Daily      0.10000000
8      Daily      0.25000000
9      Daily      0.50000000
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Assisted Solution

by:awking00
awking00 earned 250 total points
Comment Utility
select t1.id, t1.returntype, t1.returnvalue, z.rangevalue
from table1 as t1,
(select x.rangetype, x.rangevalue, y.rangevalue as nextvalue from
 (select rangetype, rangevalue,
  row_number() over (order by rangetype, rangevalue) rn
  from table2) as x,
 (select rangetype, rangevalue,
  row_number() over (order by rangetype, rangevalue) rn
  from table2) as y
 where x.rn = y.rn - 1) as z
where t1.returnvalue between z.rangevalue and z.nextvalue
order by t1.id;
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Expert Comment

by:awking00
Comment Utility
Should have added the types to the join to separate daily from weekly from monthly.
...
where t1.returnvalue between z.rangevalue and z.nextvalue
and t1.returntype = z.rangetype
...
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