?
Solved

Help with javascript function

Posted on 2013-11-14
3
Medium Priority
?
223 Views
Last Modified: 2013-11-21
I am having a hard time getting this function to work correctly. I am new to javascript and am not sure where my error is.

What I am trying to accomplish:
Logic
If the actualenddate does not exist and the plannedenddate is in the future res=None

if the actualenddate does exist and it is greater than the plannedenddate res=Behind

if the actualenddate does not exist and the plannedenddate is < today res=Delinquent

if the actualenddate does exist and is <= plannedenddate res=Ahead


function VerifyOnTime(actualEndDate,plannedEndDate){
	//alert("actual: "+actualEndDate+" planned: "+plannedEndDate);
	
	var res="NONE";
	var ped=Date.parse(plannedEndDate);
	
	var today=(new Date()).getTime();
	var aed=null;
	if (actualEndDate!='')
		aed=Date.parse(actualEndDate);
	else 
		aed=today;

	
	if (aed!='' && aed>ped){
		res='BEHIND';
	}else if (ped>=today && aed==''){
		res='NONE';
	}else if (aed=='' && ped<today){
		//alert(actualEndDate);
		//alert(ped);
		//alert(today);
		res='DELINQUENT';
	}else if (aed<=ped){
		//alert(actualEndDate);
		//alert(ped);
		//alert(today);
		res='AHEAD';
	}else{
		res='NONE';
	}

	//alert(res);
	return res;
}

Open in new window

0
Comment
Question by:J C
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 30

Accepted Solution

by:
Alexandre Simões earned 2000 total points
ID: 39650410
Something like this should do the trick:
function VerifyOnTime(actualEndDate, plannedEndDate) {
    var res = "NONE";
    var today = (new Date()).getTime();
    var ped = Date.parse(plannedEndDate);
    var aed = (actualEndDate && actualEndDate != '') ? Date.parse(actualEndDate) : null;

    if (aed > ped) {
        res = 'BEHIND';
    } else if (ped >= today && !aed) {
        res = 'NONE';
    } else if (!aed && ped < today) {
        res = 'DELINQUENT';
    } else if (aed <= ped) {
        res = 'AHEAD';
    } else {
        res = 'NONE';
    }

    return res;
}

Open in new window


Here's a working sample: http://jsfiddle.net/aLkZd/
0
 
LVL 44

Expert Comment

by:Rainer Jeschor
ID: 39650424
Hi,

something like this?
Sample:
http://jsfiddle.net/EE_RainerJ/c3zLJ/

function VerifyOnTime(actualEndDate,plannedEndDate){
      var res="NONE";
      var ped=Date.parse(plannedEndDate);
      
      var today=(new Date()).getTime();
      var aed;
      if (actualEndDate=='')
	  {
		if(ped>today) {
			return res;
		} else {
			return 'DELINQUENT';
		}
	  }
	  else {
		aed=Date.parse(actualEndDate);
		if (aed > ped) {
			return 'BEHIND';
        } else {
			return 'AHEAD';
		}
	}
} 

Open in new window

0
 

Author Closing Comment

by:J C
ID: 39666169
This worked perfectly. Thanks a lot!
0

Featured Post

Free Tool: IP Lookup

Get more info about an IP address or domain name, such as organization, abuse contacts and geolocation.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Originally, this post was published on Monitis Blog, you can check it here . It goes without saying that technology has transformed society and the very nature of how we live, work, and communicate in ways that would’ve been incomprehensible 5 ye…
Without even knowing it, most of us are using web applications on a daily basis.  In fact, Gmail and Yahoo email, Twitter, Facebook, and eBay are used by most of us daily—and they are web applications. We generally confuse these web applications to…
The viewer will learn how to dynamically set the form action using jQuery.
The viewer will learn how to count occurrences of each item in an array.

719 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question