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Please help with simple PS/SQL-script

Posted on 2013-11-15
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245 Views
Last Modified: 2013-12-12
Hi!

This works:
Select n.ID_NO,c.REMINDER_GROUP,c.CUST_NO,n.NAME_TYPE
  from TTT.NAME n, TTT.CUSTOMER c
 where c.CUST_NO = n.ID_NO
   and c.REMINDER_GROUP <> 3
   and n.NAME_TYPE = 1

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Can anyone explain why this doesn't work:
update TTT.CUSTOMER c
   set c.REMINDER_GROUP = 3
 where c.CUST_NO = TTT.NAME.ID_NO
   and c.REMINDER_GROUP <> 3
   and TTT.NAME.NAME_TYPE = 1

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And neither does this:
update cust set cust.REMINDER_GROUP = 3
    on TTT.CUSTOMER cust inner join TTT.NAME n 
 where cust.CUST_NO = n.ID_NO
   and cust.REMINDER_GROUP <> 3
   and n.NAME_TYPE = 1
 

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Thanks for any help!
0
Comment
Question by:IverErling
  • 3
  • 3
7 Comments
 
LVL 13

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 39650798
update TTT.CUSTOMER c
   set c.REMINDER_GROUP = 3
 where c.CUST_NO = TTT.NAME.ID_NO
   and c.REMINDER_GROUP <> 3
   and TTT.NAME.NAME_TYPE = 1

TTT.NAME is not referenced within the update = error

You will have to use either sub selects or inner joins or merges to solve this...

some examples:

MERGE:
MERGE INTO table_b 
USING 
(
  SELECT id,
         field_2
  FROM table_a
) ta ON (ta.id = table_b.id)
WHEN MATCHED THEN UPDATE 
    SET table_b.field_2 = ta.field_2

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SUB SELECT:
UPDATE table_a a
   SET field_2 = ( SELECT field_2
                     FROM table_b b
                    WHERE b.id = a.id )
;

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INNER JOIN:
UPDATE a
   SET a.field_2 = b.field_2
FROM table_a a
INNER JOIN table_b b
  ON a.id = b.id
;

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0
 

Author Comment

by:IverErling
ID: 39650836
Thanks for your answer, but I cannot see how any of those examples would work, as I want to set the value of REMINDER_GROUP to a fixed value of 3 for all records that match the WHERE statement. I don't want to set it to the result of a sub-query.

For each row in the TTT.CUSTOMER-table found by this query:
select c.rowid
  from TTT.NAME n, TTT.CUSTOMER c
 where n.ID_NO = c.CUST_NO
   and c.REMINDER_GROUP <> 3
   and n.NAME_TYPE = 1

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I want to set REMINDER_GROUP to 3

IVer
0
 

Author Comment

by:IverErling
ID: 39650898
Fixed it:
update CUSTOMER
   set REMINDER_GROUP = 3
 where CUST_NO in 
 (
       select cu.CUST_NO
       from NAME n
       inner join
       CUSTOMER cu
         on cu.CUST_NO = n.ID_NO
       where cu.REMINDER_GROUP <> 3
         and n.NAME_TYPE = 1
 )

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did the trick.

IVer
0
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Author Comment

by:IverErling
ID: 39650985
I've requested that this question be closed as follows:

Accepted answer: 0 points for IverErling's comment #a39650898

for the following reason:

This script did exactly what I was looking for.
0
 
LVL 13

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 39650986
I am really not after the points, but I have the feeling that this kind of closing a question is not "ok"...
0
 
LVL 35

Accepted Solution

by:
Mark Geerlings earned 500 total points
ID: 39651952
Or, this would work with a sub-query in Oracle's native (not ANSI-standard) syntax:

update TTT.CUSTOMER c
   set c.REMINDER_GROUP = 3
 where c.REMINDER_GROUP <> 3
   and c.CUST_NO in (select N.ID_NO
   from TTT.NAME N
   where N.NAME_TYPE = 1);

Also: note that this is simply an SQL syntax question.  This is not a PL\SQL question.  PL\SQL is Oracle's programming language for stored procedures.  But, your question and the proposed solutions here do not involve stored procedures.
0
 
LVL 13

Expert Comment

by:Alexander Eßer [Alex140181]
ID: 39713936
Thumbs up *rolling eyes*
Well, that went well...
0

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Network Monitoring is essential to ensure that computer systems and network devices are running. Use PRTG to monitor LANs, servers, websites, applications and devices, bandwidth, virtual environments, remote systems, IoT, and many more. PRTG is easy to set up & use.

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