Mysql get top rows

Are you looking for this?
SELECT * FROM (
SELECT ORID,COUNT(*) cnt
FROM  `FEED`
GROUP BY ORID
HAVING COUNT( * ) >2000) t1
ORDER BY cnt DESC
LIMIT 2000

I think you query gives me the  count (*). But I need the rows of Feed table itselves.
eg.

Lets say the FEED has fields  ID (PK)  and ORID,
it has
2500 records with ORID=1
1500 records with ORID=2  
3700 records with ORID=3

I need to have the list of records
First 500 records with  ORID=1 UNION First 1700 records with  ORID=3
 (Nothing from ORID=2 since #of records are less than 2000)

>> First 500 records with  ORID=1 UNION First 1700 records with  ORID=3

Do you have any date field like Update date, Modified date to order the records?

No I don't have.  The order with  ID (PK) is sufficient.

Lets say the FEED has fields  ID (PK)  and ORID,
it has
2500 records with ORID=1
1500 records with ORID=2  << ignored
3700 records with ORID=3

I need to have the list of records
First 500 records with  ORID=1 UNION First 1700 records with  ORID=3

(500+1,700) = 2,200 :: why 2,200 records?

also:
why 500 of 2,500 ? (20% of that ordid)
why 1,700 of 3,700 ? (46% of that ordid)

@PortletPaul, he needs the records excluding the first 2000, he stated this in the original post. So if an ORID has < 2000 records it would not return any rows.

this may be possible but you would need better than the community version of mysql so that you can put a LIMIT into a subquery.

Example
create a view with this as the sql statement

select ORID, count(ORID) as feed_count from feed 
group by ORID

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then make a second view (get the last 2000 records)

Select f1.id from feed as f1 where 2000 <
(Select feed_count from name_of_your_view as f2 where f2.ORID = f1.ORID)
order by ID desc

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then your query

Select * from feed f1 where ID in (select id from name_of_second_view f2 where f1.ORID = f2.ORID LIMIT 2000,18446744073709551615)
order by ORID asc

Select allOpen in new window

I think this query would also take a very long time to run.

worked! great!