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MSXML2.ServerXmlhttp.6.0 Error

Posted on 2013-11-22
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Last Modified: 2013-11-26
Set http = CreateObject("MSXML2.ServerXMLHTTP.6.0")
http.Open  "GET", "http://www.google.com", False,userid,password
http.Send
WScript.ECHO http.ResponseText

The above code creating error as below
The server name or address could not be resolved

But this is working with MSXML2.XMLHTTP
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Question by:JayeshIyer
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6 Comments
 
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Accepted Solution

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RobSampson earned 500 total points
ID: 39670818
I'm not sure that would work with Google.  Using a username and password implies you should be querying the HTTPS protocol instead of HTTP, but it may also be expecting a different URL to authenticate against.

On the other hand, if it's not resolving, are you behind a proxy that might be stopping it from reaching the URL?

If so, can you try the code from a direct link with no proxy?  Or you can try adding this:
http.setProxy 2, "myproxyserver:8080"
http.setProxyCredentials "MyUserName", "myPassword"

before the GET call.

Rob.
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LVL 65

Expert Comment

by:RobSampson
ID: 39670819
There's also a good article on MSDN for troubleshooting such code here:
http://blogs.msdn.com/b/jpsanders/archive/2008/06/25/troubleshooting-code-that-uses-the-http-protocol.aspx

Rob.
0
 

Author Comment

by:JayeshIyer
ID: 39673908
Thanks rob for your comments.
This worked for the above code.

Set http = CreateObject("MSXML2.ServerXMLHTTP.6.0")
http.Open  "GET", "https://jazz.visteon.com:9443/ccm", False,userid,password
http.setProxy 2,  "136.17.0.7:83"
http.setProxyCredentials username, password
http.Send
WScript.ECHO http.ResponseText

But when i am using different url the below error is comming


Network Error (tcp_error)
Communication error
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LVL 65

Expert Comment

by:RobSampson
ID: 39673980
Again, I'd make sure you can access that through the proxy, and try running the script from the same authorised user account as well.
0
 

Author Comment

by:JayeshIyer
ID: 39677394
Yes rob i tried without proxy settings.then it gives the below error

A connection with the server could not be established.
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LVL 65

Expert Comment

by:RobSampson
ID: 39679345
Hmmm, I guess some sites may require that you send specific headers with the request. There is code here that may help:
http://zanstra.home.xs4all.nl/inTec/ServerXMLHTTP.htm

I have put it with your current code to see what happens.

Set http = CreateObject("MSXML2.ServerXMLHTTP.6.0")
http.Open  "GET", "https://jazz.visteon.com:9443/ccm", False,userid,password
http.setProxy 2,  "136.17.0.7:83"
http.setProxyCredentials username, password
http.setOption 2, 13056
http.setRequestHeader "Authorization", "Basic " & Base64Encode(userid & ":" & password)
http.Send
WScript.ECHO http.responseText

Function Base64Encode(inData)
'ripped from: 
'http://www.pstruh.cz/tips/detpg_Base64Encode.htm
  'rfc1521
  '2001 Antonin Foller, PSTRUH Software, http://pstruh.cz
  Const Base64 = _
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
  Dim sOut, I
  
  'For each group of 3 bytes
  For I = 1 To Len(inData) Step 3
    Dim nGroup, pOut
    
    'Create one long from this 3 bytes.
    nGroup = &H10000 * Asc(Mid(inData, I, 1)) + _
      &H100 * MyASC(Mid(inData, I + 1, 1)) + _
      MyASC(Mid(inData, I + 2, 1))
    
    'Oct splits the long To 8 groups with 3 bits
    nGroup = Oct(nGroup)
    
    'Add leading zeros
    nGroup = String(8 - Len(nGroup), "0") & nGroup
    
    'Convert To base64
    pOut = Mid(Base64, CLng("&o" & Mid(nGroup, 1, 2)) + 1, 1) + _
      Mid(Base64, CLng("&o" & Mid(nGroup, 3, 2)) + 1, 1) + _
      Mid(Base64, CLng("&o" & Mid(nGroup, 5, 2)) + 1, 1) + _
      Mid(Base64, CLng("&o" & Mid(nGroup, 7, 2)) + 1, 1)
    
    'Add the part To OutPut string
    sOut = sOut + pOut
    
  Next
  Select Case Len(inData) Mod 3
    Case 1: '8 bit final
      sOut = Left(sOut, Len(sOut) - 2) + "=="
    Case 2: '16 bit final
      sOut = Left(sOut, Len(sOut) - 1) + "="
  End Select
  Base64Encode = sOut
End Function

Function MyASC(OneChar)
  If OneChar = "" Then MyASC = 0 Else MyASC = Asc(OneChar)
End Function

Open in new window


Or, if the certificate isn't quite right, you can try this to ignore certificate errors:
Set http = CreateObject("MSXML2.ServerXMLHTTP.6.0")
http.Open  "GET", "https://jazz.visteon.com:9443/ccm", False,userid,password
http.setProxy 2,  "136.17.0.7:83"
http.setProxyCredentials username, password
http.setOption 2, 13056
http.Send
WScript.ECHO http.responseText

Open in new window


Rob.
0

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