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Cisco Utilization calculation question

Posted on 2013-11-22
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Last Modified: 2013-11-23
Hello Experts,

Can someone please look at the following calculation used by a company called ManageEngine to calculate the utilization on a link and let me know how how I would use the calculation to calculate the utilization from the output taken from the interface on our router


Speed = (Volume in bits / time in seconds). Which is (Volume * 8 / 60) Reported in bits per second (bps).

Utilization = (current speed/ link speed) * 100. Current speed is calculated as above.


The following is the output from our interface. I would like someone to show me how to use the above calculation to get the the utilization:

UK01252-DM01-Paddington20ET#show int tunn 0
Tunnel0 is up, line protocol is up
  Hardware is Tunnel
  Description: ** mGRE/NHRP tunnel **
  Internet address is 172.17.141.42/24
  MTU 17912 bytes, BW 2048 Kbit/sec, DLY 50000 usec,
     reliability 255/255, txload 34/255, rxload 92/255
  Encapsulation TUNNEL, loopback not set
  Keepalive not set
  Tunnel source 217.xx.xx.xx (FastEthernet0)
  Tunnel protocol/transport multi-GRE/IP
    Key 0x30D41, sequencing disabled
    Checksumming of packets disabled
  Tunnel TTL 255
  Tunnel transport MTU 1472 bytes
  Tunnel transmit bandwidth 8000 (kbps)
  Tunnel receive bandwidth 8000 (kbps)
  Tunnel protection via IPSec (profile "vpnprofile")
  Last input 00:00:00, output never, output hang never
  Last clearing of "show interface" counters never
  Input queue: 0/256/0/0 (size/max/drops/flushes); Total output drops: 429
  Queueing strategy: fifo
  Output queue: 0/0 (size/max)
  5 minute input rate 744000 bits/sec, 115 packets/sec
  5 minute output rate 278000 bits/sec, 101 packets/sec
     536461271 packets input, 50720742 bytes, 0 no buffer
     Received 0 broadcasts, 0 runts, 0 giants, 0 throttles
     0 input errors, 0 CRC, 0 frame, 0 overrun, 0 ignored, 0 abort
     430873111 packets output, 597245969 bytes, 0 underruns
     0 output errors, 0 collisions, 0 interface resets
     0 unknown protocol drops
     0 output buffer failures, 0 output buffers swapped out

Cisco would calculate the utilization as

txload => 34/255 = 13%
rxload => 92/255 = 36%

I don't know how ManageEngines' formula would give me the same result.

Your help will be greatly appreciated.

Cheers

Carlton
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Question by:cpatte7372
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Expert Comment

by:Infamus
ID: 39669953
MTU 17912 bytes, BW 2048 Kbit/sec, DLY 50000 usec,

5 minute input rate 744000 bits/sec, 115 packets/sec
5 minute output rate 278000 bits/sec, 101 packets/sec

RxLoad = (744000/2048000)*100 = 36.328125
TxLoad = (278000/2048000)*100 = 13.57421875
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Author Comment

by:cpatte7372
ID: 39670009
Infamus,

Thanks for responding.

Can you tell me what is meant by (Volume * 8 / 60) ? And how was that used in the calculation?

Cheers
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Author Comment

by:cpatte7372
ID: 39670023
Also, your calculation is taken over 5minutes....
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Expert Comment

by:Infamus
ID: 39670031
I didn't have to calculate that since the output is already telling you the speed as I commented above. (or below for clarification)

5 minute input rate 744000 bits/sec, 115 packets/sec
5 minute output rate 278000 bits/sec, 101 packets/sec

It is the average per second rate over 5 minutes, not entire 5 minutes.
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Author Comment

by:cpatte7372
ID: 39670051
Infamus,

Can you let me know how I could use the same information to work out the utilisation over one minute instead of 5minutes?

Cheers

Carlton
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Expert Comment

by:Infamus
ID: 39670067
You have to configure the interval to 1 minute since the default is 5 minutes.

conf t

interface tunn0

load-interval 60

But why would you do that?

It will still give you the average per second rate anyways.
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Author Comment

by:cpatte7372
ID: 39670079
Hi Infamus,

So when ManageEngine use  (Volume * 8 / 60) in the calculation what are they trying achieve?

Cheers
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Accepted Solution

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Infamus earned 500 total points
ID: 39670096
Voume *8 is to convert bytes to bits and /60 to convert minute to second.

I think this calculation is to explain Speed = (Volume in bits / time in seconds).

Which is not necessary in this case since the output is already telling us the speed (bits/sec).
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Author Comment

by:cpatte7372
ID: 39670164
Hi Infamus,

I think I get it now.

Thanks mate.

Cheers
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LVL 12

Expert Comment

by:Infamus
ID: 39670202
Glad to help.
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Author Closing Comment

by:cpatte7372
ID: 39671277
Excellent
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