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VBA / Excel - inserting rows between each of several hundred rows

In column A I have several hundred rows of data.  I want create 2 copies of each row and insert it under the original row.  EG I want to insert 2 copies of row 2 just below row 2, causing what is currently row 3 to move to row 5.  I then want to repeat this for what is now row 5, and repeat until all the orignal rows  have 2 copies beneath their original row,

Then in column B, against each set of idential items in column A I want to put text string 1 against the first, text string 2 against the second and text string 3 against the 3rd.  EG after completing the procedure cells B2:B4 will contain respectively text string1 - text string 3.

I am sure this can be done in VBA but I am still a total novice with VBA so would appreciate some help.

Thanks

Eric
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childejc
Asked:
childejc
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1 Solution
 
Rgonzo1971Commented:
Hi,

pls try

Sub macro()

Set myRange = Range(Range("A2"), Range("A" & Rows.Count).End(xlUp))

For Idx = myRange.Rows.Count + 1 To 2 Step -1
    Range("A" & Idx).EntireRow.Copy
    Range("A" & Idx).Insert Shift:=xlDown
    Range("A" & Idx).EntireRow.Copy
    Range("A" & Idx).Insert Shift:=xlDown
    Range("A" & Idx).Offset(, 1) = "text string 1"
    Range("A" & Idx).Offset(1, 1) = "text string 2"
    Range("A" & Idx).Offset(2, 1) = "text string 3"
Next


End Sub

Open in new window

Regards
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childejcAuthor Commented:
Thanks!  You have saved me a lot of grief!
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Saqib Husain, SyedEngineerCommented:
Although the question is closed, there is a non VBA method if you are interested.
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childejcAuthor Commented:
Yes please, I am interested...
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Saqib Husain, SyedEngineerCommented:
Lets say your data is in column A and you want to populate column B with textstring.

Fill column C with numbers 1 to 10000 or whatever you have.
Copy A1:C10000 twice below to A10001:C20000 and A20001:C30000
Fill B1:B10000 with textstring1
Fill B10001:B20000 with textstring2
Fill B20001:B30000 with textstring3
Sort A1:C30000 with column C as the primary key and column B as secondary key
Delete column C
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childejcAuthor Commented:
Good idea, I can see that woudl also do the job, and probably more quickly, and I will bear it in mind for the future.

The VBA code provided earlier is still running as we speak churning through my data, and is somewhat slower than I expected.  However I am trying to learn VBA and so this was a good opportunity to learn something relevant to my actual current needs, so I did want a VBA solution.  Now I just need to try to understand it!
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Saqib Husain, SyedEngineerCommented:
I suggest that you
halt the macro,
turn off automatic calculation mode,
resume the macro,
when it ends turn on automatic calculation mode.
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Rgonzo1971Commented:
Hi,

I should have integrated Screenupdating false

Sub macro()

Application.ScreenUpdating = False
Set myRange = Range(Range("A2"), Range("A" & Rows.Count).End(xlUp))

For idx = myRange.Rows.Count + 1 To 2 Step -1
    Range("A" & idx).EntireRow.Copy
    Range("A" & idx).Insert Shift:=xlDown
    Range("A" & idx).EntireRow.Copy
    Range("A" & idx).Insert Shift:=xlDown
    Range("A" & idx).Offset(, 1) = "text string 1"
    Range("A" & idx).Offset(1, 1) = "text string 2"
    Range("A" & idx).Offset(2, 1) = "text string 3"
Next
Application.ScreenUpdating = True
End Sub

Open in new window

Regards
0
 
Saqib Husain, SyedEngineerCommented:
I think in this case recalculation is more critical as he has spent over an hour. Screenupdating is also good.
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Rgonzo1971Commented:
HI,

adjusted code

Sub macro()

myCalc = Application.Calculation
Application.Calculation = xlCalculationManual
Application.ScreenUpdating = False
Set myRange = Range(Range("A2"), Range("A" & Rows.Count).End(xlUp))

For idx = myRange.Rows.Count + 1 To 2 Step -1
    Range("A" & idx).EntireRow.Copy
    Range("A" & idx).Insert Shift:=xlDown
    Range("A" & idx).EntireRow.Copy
    Range("A" & idx).Insert Shift:=xlDown
    Range("A" & idx).Offset(, 1) = "text string 1"
    Range("A" & idx).Offset(1, 1) = "text string 2"
    Range("A" & idx).Offset(2, 1) = "text string 3"
Next
Application.Calculation = myCalc
Application.ScreenUpdating = True
End Sub

Open in new window

Regards
0
 
childejcAuthor Commented:
Thanks for this - I am new to this site and am very impressed by the quality of responses and helpfulness of contributors.

It took about 1.5 hours in the end (around 500 rows with 8 duplications for each row), and I did not see this response until it was done.  However I need to repeat the process for another sheet with around 400 rows, so will use this modified code (with manual calculation) for that to see how it improves matters.

Thanks again

Eric
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