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Parsing XML

Posted on 2013-11-26
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Last Modified: 2013-11-26
I am receiving an xml response as shown.  How do I get the SubscriptionId value from the xml?

<code>

Dim post_response As String, mmsg As String, subid As String


        post_response = "<?xml version=""1.0"" encoding=""utf-8""?><ARBCreateSubscriptionResponse xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns=""AnetApi/xml/v1/schema/AnetApiSchema.xsd"">"
        post_response &= "<refId>6290</refId>"
        post_response &= "<messages>"
        post_response &= "<resultCode>Ok</resultCode>"
        post_response &= "<message>"
        post_response &= "<code>I00001</code>"
        post_response &= "<text>Successful.</text>"
        post_response &= "</message>"
        post_response &= "</messages>"
        post_response &= "<subscriptionId>1893589</subscriptionId>"
        post_response &= "</ARBCreateSubscriptionResponse>"



        BookingXML.LoadXml(post_response)

            mmsg = BookingXML.ChildNodes(1).Item("messages").FirstChild.ChildNodes(0).InnerText
           
            If UCase(mmsg) = "OK" Then
                subid = ??
            End If

</code>
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Question by:john
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Accepted Solution

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zc2 earned 500 total points
ID: 39678491
I consider that ChildNodes traversing very unreliable.
Try to use the XPath selection, it's much more convenient.

Dim nsmgr As New XmlNamespaceManager(BookingXML.NameTable)
nsmgr.AddNamespace("anet", "AnetApi/xml/v1/schema/AnetApiSchema.xsd")
subid = BookingXML.SelectSingleNode("//anet:subscriptionId", nsmgr).InnerText

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