?
Solved

Data type mismatch

Posted on 2013-11-26
9
Medium Priority
?
546 Views
Last Modified: 2013-11-26
Hi,
With these codes, against Access DB
                    cmd = new OleDbCommand("insert into ite_tab (ite_abbr,ite_name,obj2_id,obj2,obj3_id,obj3,ent_id,obj4cat,typ2_id,obj4group,typ3_id,obj4title,obj5_typ4_fullname,obj5_typ4_name,obj5_typ4_ext,ite_fld10,fld11,fld12,fld13,fld14,fld15,ite_dt,fld5,chg_date,fld6,upd_date) values (@par_id,@name,@obj2_id,@obj2,@obj3_id,@obj3,@ent,@obj4cat,@ent_grp_id,@obj4group,@typ3_id,@obj4title,@fl_fullname,@fl_name,@fl_ext,@pass,@fld11,@fld12,iif(isnull(@fld13),'',@fld13),iif(isnull(@fld14),'',@fld14),iif(isnull(@fld15),'',@fld15),@ite_dt,datediff('yyyy',@ite_dt2,Date()),@chg_dt,@fld6,Date())", conn);
                    if (tb_iteabbr != null)
                    {
                        id2 = tb_iteabbr.Text.Trim();
                    }

                    name = tb_itename.Text.Trim();
                    fl_fullname = tb_ph_typ4_fullname.Text.Trim();
                    fl_name = tb_ph_typ4_name.Text.Trim();
                    cmd.Parameters.Add("@par_id", OleDbType.VarChar).Value = id2;
                    cmd.Parameters.Add("@name", OleDbType.VarChar).Value = name;
                    cmd.Parameters.Add("@obj2_id", OleDbType.VarChar).Value = obj2_ddl.SelectedValue.ToString();
                    cmd.Parameters.Add("@obj2", OleDbType.VarWChar).Value = obj2_ddl.SelectedItem.ToString();
                    cmd.Parameters.Add("@obj3_id", OleDbType.VarChar).Value = obj3_ddl.SelectedValue.ToString();
                    cmd.Parameters.Add("@obj3", OleDbType.VarWChar).Value = obj3_ddl.SelectedItem.ToString();
                    cmd.Parameters.Add("@ent", OleDbType.VarChar).Value = ent_cat_ddl.SelectedValue.ToString();
                    cmd.Parameters.Add("@obj4cat", OleDbType.VarChar).Value = ent_cat_ddl.SelectedItem.ToString();
                    cmd.Parameters.Add("@ent_grp_id", OleDbType.VarChar).Value = typ2_ddl.SelectedValue.ToString();
                    cmd.Parameters.Add("@obj4group", OleDbType.VarChar).Value = typ2_ddl.SelectedItem.ToString();
                    cmd.Parameters.Add("@typ3_id", OleDbType.VarChar).Value = typ3_ddl.SelectedValue.ToString();
                    cmd.Parameters.Add("@obj4title", OleDbType.VarChar).Value = typ3_ddl.SelectedItem.ToString();
                    cmd.Parameters.Add("@pass", OleDbType.VarChar).Value = new_pass;
                    cmd.Parameters.Add("@fl_fullname", OleDbType.VarChar).Value = fl_fullname;
                    cmd.Parameters.Add("@fl_name", OleDbType.VarChar).Value = fl_name;
                    cmd.Parameters.Add("@fl_ext", OleDbType.VarChar).Value = tb_flext.Text;
                    cmd.Parameters.Add("@chg_dt", OleDbType.DBDate).Value = Convert.ToDateTime(tb_chg_dt.Text.Trim());
                    cmd.Parameters.Add("@fld11", OleDbType.Decimal).Value = Convert.ToDecimal(tb_fld11.Text);
                    cmd.Parameters.Add("@fld12", OleDbType.Decimal).Value = Convert.ToDecimal(tb_fld12.Text);
                    cmd.Parameters.Add("@fld13", OleDbType.VarChar).Value = tb_fld13.Text;
                    cmd.Parameters.Add("@fld14", OleDbType.VarChar).Value = tb_fld14.Text;
                    cmd.Parameters.Add("@fld15", OleDbType.VarChar).Value = tb_fld15.Text;
                    cmd.Parameters.Add("@ite_dt", OleDbType.DBDate).Value = DateTime.ParseExact(tb_ite_dt.Text.Trim(), "dd/MM/yyyy", CultureInfo.InvariantCulture);
                    cmd.Parameters.Add("@ite_dt2", OleDbType.DBDate).Value = DateTime.ParseExact(tb_ite_dt.Text.Trim(), "dd/MM/yyyy", CultureInfo.InvariantCulture);
                    cmd.Parameters.Add("@fld6", OleDbType.VarChar).Value = rbl_fld6.SelectedItem.Text;
                    cmd.ExecuteNonQuery();

Open in new window


I do get this exception. why?
Data type mismatch in criteria expression.Microsoft Access Database Engine
0
Comment
Question by:HuaMinChen
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 5
  • 4
9 Comments
 
LVL 25

Expert Comment

by:chaau
ID: 39679605
Why do you use OleDbType.VarWChar for "@obj3" and OleDbType.VarChar for others?
0
 
LVL 25

Expert Comment

by:chaau
ID: 39679608
Can you post here the "ite_tab" table structure
0
 
LVL 11

Author Comment

by:HuaMinChen
ID: 39679610
As this column can have unicode inside.
0
Docker-Compose to Simplify Multi-Container Builds

Our veteran DevOps Author takes you through how to build a multi-container environment, managed with a single utility in order to simplify your deployments.

 
LVL 11

Author Comment

by:HuaMinChen
ID: 39679639
I've changed a little bit in these 2 lines (but I still get the same exception after the change)

                    cmd.Parameters.Add("@fld11", OleDbType.Integer).Value = Convert.ToInt32(tb_fld11.Text);
                    cmd.Parameters.Add("@fld12", OleDbType.Integer).Value = Convert.ToInt32(tb_fld12.Text);

Open in new window

only these 2 columns, those column names like ".._id" are numbers,

these 4 columns are Date/Time
ite_dt,fld5,chg_date,upd_date

all other columns are Short Text.
0
 
LVL 25

Expert Comment

by:chaau
ID: 39679737
You are trying to insert datediff('yyyy',@ite_dt2,Date()) into a date/time column. Datediff returns integer.
You need to insert a date value. What was your intention when you have written this datediff statement?
0
 
LVL 11

Author Comment

by:HuaMinChen
ID: 39679743
Sorry, actually

fld5

is also one Date/Time column. thanks
0
 
LVL 25

Expert Comment

by:chaau
ID: 39679777
That is why I have asked. What are you trying to have inserted into this column? You will not be able to insert a result of datediff('yyyy',@ite_dt2,Date()) function. Just tell me what are you intentions, and I can help you out
0
 
LVL 11

Author Comment

by:HuaMinChen
ID: 39679785
Just the difference of 2 dates, which is a number, and also the column data type is number as well.
0
 
LVL 25

Accepted Solution

by:
chaau earned 435 total points
ID: 39679787
Can you change temporarily obj2 to Char and see if it works:
                    cmd.Parameters.Add("@obj2", OleDbType.VarChar).Value = obj2_ddl.SelectedItem.ToString();

Open in new window

0

Featured Post

 [eBook] Windows Nano Server

Download this FREE eBook and learn all you need to get started with Windows Nano Server, including deployment options, remote management
and troubleshooting tips and tricks

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Phishing attempts can come in all forms, shapes and sizes. No matter how familiar you think you are with them, always remember to take extra precaution when opening an email with attachments or links.
Access developers frequently have requirements to interact with Excel (import from or output to) in their applications.  You might be able to accomplish this with the TransferSpreadsheet and OutputTo methods, but in this series of articles I will di…
In Microsoft Access, when working with VBA, learn some techniques for writing readable and easily maintained code.
With Secure Portal Encryption, the recipient is sent a link to their email address directing them to the email laundry delivery page. From there, the recipient will be required to enter a user name and password to enter the page. Once the recipient …
Suggested Courses
Course of the Month14 days, 11 hours left to enroll

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question