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JackW9653

asked on 12/2/2013

Trailing String Characters in SQL Statement

Hi Experts,

I'm trying to compile a list of ';' separated values from 10 fields in a SQL table but I'm left with ';' at the end of my string. Here's my query:

SELECT STUFF(
(SELECT '; '+ SUBSTRING(Alert1,CHARINDEX('^',Alert1)+1, LEN(Alert1))+ '; ' +
      COALESCE(SUBSTRING(Alert2, CHARINDEX('^', ALERT2)+1, LEN(Alert2)),'') + '; ' +
      COALESCE(SUBSTRING(Alert3, CHARINDEX('^', ALERT3)+1, LEN(Alert3)),'') + '; ' +
      COALESCE(SUBSTRING(Alert4, CHARINDEX('^', ALERT4)+1, LEN(Alert4)),'') + '; ' +
      COALESCE(SUBSTRING(Alert5, CHARINDEX('^', ALERT5)+1, LEN(Alert5)),'') + '; ' +
      COALESCE(SUBSTRING(Alert6, CHARINDEX('^', ALERT6)+1, LEN(Alert6)),'') + '; ' +
      COALESCE(SUBSTRING(Alert7, CHARINDEX('^', ALERT7)+1, LEN(Alert7)),'') + '; ' +
      COALESCE(SUBSTRING(Alert8, CHARINDEX('^', ALERT8)+1, LEN(Alert8)),'') + '; ' +
      COALESCE(SUBSTRING(Alert9, CHARINDEX('^', ALERT9)+1, LEN(Alert9)),'') + '; ' +
      COALESCE(SUBSTRING(Alert10,CHARINDEX('^',Alert10)+1, LEN(Alert10)),'')
FROM tblPatientData
WHERE CaseNumber = '10223001'
FOR XML PATH ('')),1,1,'') AS RESULTS

And Results:

EPILEPSY; RISK OF FALLS; DIZZINESS; HIV/AIDS; A-FIB ; ; ; ; ;

It's highly doubtful any patient will exceed 5 Alerts so getting rid of the trailing ';' is imperative. I've just ran out of time on this one.

Thanks in advance,

JackW9653

Microsoft SQL ServerMicrosoft SQL Server 2008

Last Comment

JackW9653

8/22/2022 - Mon

ASKER CERTIFIED SOLUTION

12/2/2013

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JackW9653

12/2/2013

ASKER

Good idea; here's the finished query:

SELECT STUFF(
(SELECT '; '+ SUBSTRING(Alert1,CHARINDEX('^', Alert1)+1, LEN(Alert1))+ '; ' +
      CASE WHEN ISNULL(Alert2, '') <> ''THEN COALESCE(SUBSTRING(Alert2, CHARINDEX('^', ALERT2)+1, LEN(Alert2)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert3, '') <> ''THEN COALESCE(SUBSTRING(Alert3, CHARINDEX('^', ALERT3)+1, LEN(Alert3)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert4, '') <> ''THEN COALESCE(SUBSTRING(Alert4, CHARINDEX('^', ALERT4)+1, LEN(Alert4)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert5, '') <> ''THEN COALESCE(SUBSTRING(Alert5, CHARINDEX('^', ALERT5)+1, LEN(Alert5)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert6, '') <> ''THEN COALESCE(SUBSTRING(Alert6, CHARINDEX('^', ALERT6)+1, LEN(Alert6)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert7, '') <> ''THEN COALESCE(SUBSTRING(Alert7, CHARINDEX('^', ALERT7)+1, LEN(Alert7)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert8, '') <> ''THEN COALESCE(SUBSTRING(Alert8, CHARINDEX('^', ALERT8)+1, LEN(Alert8)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert9, '') <> ''THEN COALESCE(SUBSTRING(Alert9, CHARINDEX('^', ALERT9)+1, LEN(Alert9)),'') + '; ' ELSE '' END +
      CASE WHEN ISNULL(Alert10, '') <> ''THEN COALESCE(SUBSTRING(Alert10,CHARINDEX('^',Alert10)+1, LEN(Alert10)),'') ELSE '' END
FROM tblPatientData
WHERE CaseNumber = '10223001'
FOR XML PATH ('')),1,1,'') AS RESULTS

Thanks for your help.

JackW9653

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