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get file names of directory

Posted on 2013-12-03
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Last Modified: 2013-12-04
Hi,

I am using C with Visual Studio 2010. I need help to get file names of directory. Can anyone please help me how to get file names of directory.

Thanks
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Question by:Johny12345
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11 Comments
 
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Expert Comment

by:AndyAinscow
ID: 39692797
This is what you wanted:
http://msdn.microsoft.com/en-us/library/07wt70x2%28v=vs.110%29.aspx?cs-save-lang=1&cs-lang=cpp#code-snippet-1

Directory::GetFiles(path) Method - retrieves the files in a directory supplied to the method.
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Expert Comment

by:Zoppo
ID: 39692798
Hi Johny12345,

you can use FindFirstFile and FindNextFile from Win API like i.e. demonstrated here: http://cboard.cprogramming.com/windows-programming/83267-msdn-example-code-findfirstfile-findnextfile.html

Hope that helps,

ZOPPO
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Expert Comment

by:AndyAinscow
ID: 39692804
ps.  It has an example program there demonstrating the usage
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Expert Comment

by:AndyAinscow
ID: 39692813
Note - my comment uses C++.net (one of your tags), the comment from Zoppo is using classical C (not .NET)
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Author Comment

by:Johny12345
ID: 39692877
I have used code like this but it is not taking directory properly, can anyone help me please

void getFiles(char *address)
{
 printf(address );  // this line is showing strange characters
 WIN32_FIND_DATA FindFileData;
   HANDLE hFind = INVALID_HANDLE_VALUE;
   DWORD dwError;
   LPSTR DirSpec;
   size_t length_of_arg;
 
 
   DirSpec = (LPSTR) malloc (BUFSIZE);
    
   // Check for command-line parameter; otherwise, print usage.
   if(argc != 2)
   {
      printf("Usage: Test <dir>\n");
      return 2;
   }
 
   // Check that the input is not larger than allowed.
   StringCbLength(argv[1], BUFSIZE, &length_of_arg);
   if (length_of_arg > (BUFSIZE - 2))
   {
      printf("Input directory is too large.\n");
      return 3;
   }

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Expert Comment

by:Zoppo
ID: 39692901
Could you post the code where you call the function?
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Author Comment

by:Johny12345
ID: 39692922
it is bit difficult to post all code because it too big but I am posting related code here:

int main(int argc, char *argv[])
{

char* directory_path;

directory_path = (char*) malloc(strlen(argv[2])+4);
getFiles(TEXT(directory_path));

}

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Accepted Solution

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Zoppo earned 500 total points
ID: 39692940
Well, the directory_path is allocated but the data it points to is uninitialized.

IMO you don't need to allocate a string at all, you can simply call something like:

if ( argc > 2 )
{
 getFiles( argv[2] );
}

ZOPPO
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Author Comment

by:Johny12345
ID: 39693325
thanks it worked. Is it possible to put names in dynamic array? Do I need to open another question for it?
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Author Closing Comment

by:Johny12345
ID: 39693328
great.. thanks
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Expert Comment

by:Zoppo
ID: 39694831
Hi,

you're welcome, I'm glad I could help.

About dynamic array: I guess you want to be able to return the list of found filenames to the calling function, right?

Using a C-Array in this case (usually with pointer to pointer, i.e. char**) is IMO not the best solution since you don't know the number of entries, i.o.w. you don't know how many char* you need to allocate which means you'll have to realloc the buffer repeatedly.

Maybe a better idea would be to implement some simple linked list, if needed it's easy to move it into an array afterwards with only one allocation.

Do you know how to implement a simple single linked list in C?

BTW: Just to go sure I would like to ask if you are really using plain C or if you even could use C++, many things are much easier with C++ and STL, with other libraries like i.e. BOOST you can do what you need really simpel (beside the fact if it's new for you you'll have to invest quite some time to get familiar with it).

ZOPPO
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