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java spring ClassPathResource

Posted on 2013-12-04
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Last Modified: 2013-12-21
Hi,
I am getting the following exception :

java.io.FileNotFoundException: class path resource [xsl/ExtremeSearchRQ.xsl] cannot be resolved to absolute file path because it does not reside in the file system: jar:file:/data/ytxdist/SCHEDULER/ExtremeSearch/libs/yatra_extremesearch.jar!/xsl/ExtremeSearchRQ.xsl

The following code throws this exception :
String xslSourceFile = "xsl/ExtremeSearchRQ.xsl";
		String xmlSource = "ExtremeSearchRQ.xml";
		Writer paramWriter = new StringWriter();
		
		Transformer transformer=null;
		ClassPathResource resource = new ClassPathResource(xslSourceFile);
		StreamSource streamSrcFile;
		
		streamSrcFile = new StreamSource(resource.getFile());

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The exception is thrown by the resource.getFile() line.

I am running my project with the following line :
java -cp "libs/*:conf" com.yatra.extremesearch.app.ExtremeSearchApp

Here the libs folder contains the yatra_extremesearch.jar file
when i unzip the jar i also see the file xsl/ExtremeSearchRQ.xsl

Still its giving an exception saying fileNot Found

What could be reason for this.

Thanks
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Question by:Rohit Bajaj
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Accepted Solution

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mccarl earned 500 total points
ID: 39695144
The actual detail in the error message is the more useful part
because it does not reside in the file system
Files that are inside a jar do NOT strictly "reside on the file system", eg. you can't, as an example, open up a text editor and navigate directly to your xsl file inside the JAR. Yes you can unzip it and get access to it, but unzipping it basically means that you ARE making a copy of it on the file system.

However, don't despair... Even though you can't directly resolve a "File" object for that resource, you can still access the data. Simply change line 9 of the above to this...
		streamSrcFile = new StreamSource(resource.getInputStream());

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