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Query Syntax needed

Posted on 2013-12-04
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Last Modified: 2013-12-04
I want to bring out the latest price for a number of items from a table. In MsAccess I can use the Last() function:

SELECT StockCode.StockName, Last(UnitCost) AS Cost
FROM PurchaseOrderDetails GROUP BY StockCode,StockName

The last() function is not available in SQL Server, but in my table there is an Identity RecordNo field. So I could use the Max() value of that, but I'm unsure of how to bring out the UnitCost field. If I include it within the Group By clause, I get every different price for each item. If I omit it from the Group By clause I get an error.  I just want it to select the UnitCost which is on the record with the maximum value in RecordNo. So how do I modify the following statement in order to make it work?

SELECT  Max(REcordNo),  StockCode.StockName,UnitCost AS Cost
FROM PurchaseOrderDetails GROUP BY StockCode,StockName
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Question by:TownTalk
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5 Comments
 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 39695294
try
SELECT  REcordNo,  StockCode.StockName, UnitCost AS Cost
FROM PurchaseOrderDetails A
inner join  (select max(recordno) from PurchaseOrderDetails GROUP BY StockCode, StockName) B on A.RecordNo = B.RecordNo
0
 
LVL 32

Expert Comment

by:Ephraim Wangoya
ID: 39695302
Correction

SELECT  RecordNo,  StockCode, StockName, UnitCost AS Cost
FROM PurchaseOrderDetails A 
inner join (select max(recordno) [RecordNo] from PurchaseOrderDetails GROUP BY StockCode, StockName) B on A.RecordNo = B.RecordNo

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Author Comment

by:TownTalk
ID: 39695335
Almost there I think. It gives an error: Ambiguous column name 'RecordNo'.
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LVL 32

Accepted Solution

by:
Ephraim Wangoya earned 500 total points
ID: 39695406
no problem, prefix it with A

SELECT  A.RecordNo,  StockCode, StockName, UnitCost AS Cost
FROM PurchaseOrderDetails A 
inner join (select max(recordno) [RecordNo] from PurchaseOrderDetails GROUP BY StockCode, StockName) B on A.RecordNo = B.RecordNo

Open in new window

0
 

Author Comment

by:TownTalk
ID: 39695461
Ok that works nicely now thank you.

Ian
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