asked on

SQL Query - Compare Date Part of DateTime Value in Table

Good Day Experts!

It feels like my little quandry is feasible, but I have been unable to find a solution for it.

I have SQL table data in a date column:
12/6/2013 11:48:03 AM
12/6/2013 10:05:43 AM
12/6/2013 9:25:07 AM

The User enters a Date for Start and End.
When I build my query, how do I just compare the date part of the above data?

If the User enters 12/6/2013 for both Start and End dates, I want to return all the above values.

Thanks,
jimbo99999

Brian Crowe

This is somewhat dependent on what version of SQL you are using. SQL 2008 introduced a new DATE datatype that does not have a time component so the fastest way now to strip the time component from a DATETIME is to convert to DATE.

SELECT ...
FROM myTable
WHERE CAST(dateColumn AS DATE) >= @StartDate
AND CAST(dateColumn AS DATE) <= @EndDate

Jimbo99999

ASKER

Ok, ours is pre-2008.

ASKER CERTIFIED SOLUTION

Brian Crowe

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JimFive

Pre 2008 you can CAST(CAST(datefield as INT) as datetime) to strip off the time.

Brian Crowe

Casting to INT rounds up to the next day if the time is after 12:00PM

DECLARE @date DATETIME
SET @date = '1/1/2013 13:00'

SELECT CAST(CAST(@date AS INT) AS DATETIME)

returns '1/2/2013'

SOLUTION

JimFive

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Brian Crowe

If performance is an issue than manipulating your parameters would make more efficient use of an index on the date field.

SELECT @EndDate =
CASE
WHEN @StartDate = @EndDate THEN DATEADD(DAY, 2, @EndDate)
ELSE DATEADD(DAY, 1, @EndDate)
END

SELECT ...
FROM myTable
WHERE dateColumn >= @StartDate
AND dateColumn < @EndDate

SOLUTION

SAMIR BHOGAYTA

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Jimbo99999

ASKER

Thanks everyone for your repsonses. We had other trouble last Friday that had to be put out. So, I am just gettign back to this little project of mine.

SOLUTION

Scott Pletcher

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SOLUTION

Monica P

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Jimbo99999

ASKER

Thanks for all the help everyone. I have learned quite a bit about dates. I will file this question in my knowledge base for future reference.

Thanks,
jimbo99999