?
Solved

Extract column values from combine string  data

Posted on 2013-12-07
11
Medium Priority
?
214 Views
Last Modified: 2013-12-12
Dear Experts,

I have these common data patterns (City, State Zip) as Location, and I want them to split into 3 accordingly using regex and /or substring combination under VB.Net environment:

The actual data looks like as follows:

Atlanta, GA 30315    
to break into:

Atlanta
GA
30315

Kansas City, KS 66016
to break into:

Kansas City
KS
66016


Thanks








Best solution would be greatly appreciated.


Thanks
0
Comment
Question by:JimiJ13
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 5
  • 5
11 Comments
 
LVL 52

Assisted Solution

by:Rgonzo1971
Rgonzo1971 earned 400 total points
ID: 39702923
Hi

pls try

strAddress = "Atlanta, GA 30315"

str1 = Split(strAddress, ",")(0)
str2 = Split(Trim(Split(strAddress, ",")(1)), " ")(0)
str3 = Split(Trim(Split(strAddress, ",")(1)), " ")(1)

Open in new window

Regards
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 39703101
Hi JimiJ13;

Here is sample code using regular expression to parse the Location string.

' Locations to be parsed
Dim Locations As New List(Of String)() From { "Atlanta, GA 30315", "Kansas City, KS 66016" }
' The regular expression with named groups
Dim pattern As String = "(?<City>[^,]+),\s+(?<State>[^\s]+)\s+(?<Zip>\d+)"

' Get each individual location
For Each Location In Locations
    ' Find the individual locations
    Dim match As Match = Regex.Match(Location, pattern)
    ' Access the three members by using group names
    Console.WriteLine("City = {0}  :  State = {1}  :  Zip = {2}", _
        match.Groups("City").Value, _
        match.Groups("State").Value, _
        match.Groups("Zip").Value )
Next

Open in new window

0
 

Author Comment

by:JimiJ13
ID: 39703521
Hi Rgonzo1971,

Your suggestion works great for a perfect data pattern. However, I see some data with extra spaces between values that resulted to inaccurate outputs.

Any idea how to deal with it?  


Thanks.
0
What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

 
LVL 63

Expert Comment

by:Fernando Soto
ID: 39703525
Can you give an example of, " I see some data with extra spaces between values that resulted to inaccurate outputs. ", so that I may try and adjust the pattern.
0
 

Assisted Solution

by:JimiJ13
JimiJ13 earned 0 total points
ID: 39703528
Hi  FernandoSoto,

Your solution works. Nevertheless, since this will be applied at one data at a time in the Add/Edit page, I just thought that a more specific for a single-line  record method must be more efficient.

What do you think?

Thanks.
0
 
LVL 63

Accepted Solution

by:
Fernando Soto earned 1200 total points
ID: 39703541
Hi JimiJ13;

As long as you define the pattern string before using the regex this is all that is needed.

Dim match As Match = Regex.Match(Location, pattern)

Location in the statement is the instance of the string to be parsed and match holds the parsed data. That is a one liner.
0
 

Author Comment

by:JimiJ13
ID: 39703571
Hi Fernando,

The unusual pattern that I saw is something like this:

Kansas City  , KS   66016


Thanks.
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 39703653
Because the string may not be in the correct format we will reformat the string before using it. Before using the Location variable in the regex do this first and everything else stays the same.

Dim Location As String = Regex.Replace("Kansas City  , KS   66016", "\s{2,},", ",")

Of course you will replace the string "Kansas City  , KS   66016" with the variable of the string needing to be parsed.
0
 

Author Comment

by:JimiJ13
ID: 39705543
Hi Fernando,

On the actual implementation of your solution, I got error that says:

"Location is not declared or may be inaccessible due to Protection Level"


Any idea?
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 39705898
Hi JimiJ13;

Location is just the variable name I used to represent the data to be parsed, just change it to what you are using to hold the string to be parsed.
0
 

Author Closing Comment

by:JimiJ13
ID: 39713686
Fernando has the great solution!
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Article by: Kraeven
Introduction Remote Share is a simple remote sharing tool, enabling you to see, add and remove remote or local shares. The application is written in VB.NET targeting the .NET framework 2.0. The source code and the compiled programs have been in…
Parsing a CSV file is a task that we are confronted with regularly, and although there are a vast number of means to do this, as a newbie, the field can be confusing and the tools can seem complex. A simple solution to parsing a customized CSV fi…
Add bar graphs to Access queries using Unicode block characters. Graphs appear on every record in the color you want. Give life to numbers. Hopes this gives you ideas on visualizing your data in new ways ~ Create a calculated field in a query: …
Sometimes it takes a new vantage point, apart from our everyday security practices, to truly see our Active Directory (AD) vulnerabilities. We get used to implementing the same techniques and checking the same areas for a breach. This pattern can re…
Suggested Courses

777 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question