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listbox always returns null though item is programmatically selected

hi guys,

this question has been asked quite a few times before and i've been doing some searching but i can't really pinpoint it.

i have a listbox - value list and non-multiselect. is use the

me.listbox.selected(0) = true

line of code to select the 1st row and then i try and retrieve the value using

msgbox listbox

it always comes up as a null value.

according to this thread DoDahD says we've got to use the default value of the listbox to set the value, not just aesthetically highlight the first row

http://www.experts-exchange.com/Microsoft/Development/MS_Access/Q_27245421.html

however reading other threads it seems that there could be other ways. i'm not sure and here's a quick sample database attached to demonstrate / test this

Question --> how can i select a row from the listbox aesthetically and in the value at the same time?
Listbox-Problem.mdb
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developingprogrammer
Asked:
developingprogrammer
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2 Solutions
 
BitsqueezerCommented:
Hi,

it's really simple: Set the value of the listbox to the wanted one, not the selection.

Me.lstTesting = 1

In this case it is selected and the value is set. You only need to use the value of the bound column. That of course only works if you do not have multi-select on as there is no single value in this case. Here you need to use the selection and then go through the selection collection to find out which one is selected.

Cheers,

Christian
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developingprogrammerAuthor Commented:
thanks Christian!! = ))

the above attached database is just a proof of concept but in my real database i'm dynamically filling in all the worksheets of an excel workbook. so i don't know the value before hand.

i could of course use the column property and get the value of the first row first column, but i was wonder - is there a "lazier" way to do it? = P  = ))
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Dale FyeCommented:
Use the itemdata property of the list:

me.lstTesting = me.lstTesting.itemdata(0)

or, if you have the Column headers turned on:

me.lstTesting = me.lstTesting.itemdata(1)
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developingprogrammerAuthor Commented:
fantastic advice fyed, i'll use just that! thanks!! = ))
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