Solved

SQL Statement - comparing 2 results

Posted on 2013-12-09
5
350 Views
Last Modified: 2013-12-10
Table 1                        Table 2      

AnimalID, COUNT(AnimalID)      AnimalID, Count(AnimalID)

Cat      1                  Cat      4
Dog      4                  Dog       4
Hippo      5            Snake      3
Cow      1                  Frog      4
Frog      2                  Horse      5
                        Sheep      1
                        Pig      3


And I need the resultset to be Table 1 minus Table 2

Cat      -3
Dog      0
Hippo      5
Cow      1
Frog      -2
Snake       -3
Horse      -5
Sheep      -1
Pig      -3

So the first column is an AnimalID, the 2nd is the count of AnimalID.  This information would be the result of Table 1 "SELECT AnimalID, COUNT(AnimalID)FROM Farms WHERE FarmID = 89" and Table 2 "SELECT AnimalID, COUNT(AnimalID)FROM Houses WHERE HouseID = 54"

Any ideas?  I feel like the answer is easy and I should know how to do this but it's not coming to me, help!
0
Comment
Question by:ProdigyOne2k
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
5 Comments
 
LVL 66

Expert Comment

by:Jim Horn
ID: 39707575
Probably a number of ways to pull this off, but the one that immediately comes to mind is...
SELECT AnimalID, SUM(the_count) as total
FROM (
   SELECT AnimalID, COUNT(AnimalID) as the_count
   FROM Table1
   GROUP BY AnimalID
   UNION ALL
   SELECT AnimalID, COUNT(AnimalID) * -1 as the_count
   FROM Table2
   GROUP BY AnimalID) t
GROUP BY AnimalID
ORDER BY AnimalID

Open in new window

0
 
LVL 27

Accepted Solution

by:
Chris Luttrell earned 500 total points
ID: 39707588
Something like this:
SELECT  COALESCE(T1.AnimalId,T2.AnimalId) AS AnimalId,
        COALESCE(T1.Cnt,0) - COALESCE(T2.Cnt,0) Results
FROM
(SELECT AnimalId, COUNT(AnimalId) Cnt FROM Table1 GROUP BY AnimalId) AS T1
FULL OUTER JOIN
(SELECT AnimalId, COUNT(AnimalId) Cnt FROM Table2 GROUP BY AnimalId) T2
ON T2.AnimalId = T1.AnimalId

Open in new window

0
 
LVL 66

Expert Comment

by:Jim Horn
ID: 39707672
ProdigyOne2k - Did you try my solution?  Just curious.
0
 
LVL 66

Expert Comment

by:Jim Horn
ID: 39708479
Actually, the FULL OUTER JOIN looks like the superior solution, as when I ran both and viewed the SET STATISTICS IO ON, the UNION ALL executed in 115ms, and the FULL OUTER JOIN executed in 4ms.

SET SHOWPLAN_XML OFF
GO

IF EXISTS (SELECT name FROM sys.tables WHERE name='animals1') 
	DROP TABLE animals1
GO

IF EXISTS (SELECT name FROM sys.tables WHERE name='animals2') 
	DROP TABLE animals2
GO

CREATE TABLE animals1 (AnimalID varchar(15)) 
CREATE TABLE animals2 (AnimalID varchar(15)) 

INSERT INTO animals1 (AnimalID)
VALUES 
	('Cat'), 
	('Dog'), ('Dog'), ('Dog'), ('Dog'), 
	('Hippo'), ('Hippo'), ('Hippo'), ('Hippo'), ('Hippo'),
	('Cow'), 
	('Frog'), ('Frog')

INSERT INTO animals2 (AnimalID)
VALUES 
	('Cat'), ('Cat'), ('Cat'), ('Cat'), 
	('Dog'), ('Dog'), ('Dog'), ('Dog'), 
	('Snake'), ('Snake'), ('Snake'), 
	('Frog'), ('Frog'), ('Frog'), ('Frog'), 
	('Horse'), ('Horse'), ('Horse'), ('Horse'), ('Horse'),
	('Sheep'), 
	('Pig'), ('Pig'), ('Pig')


SET STATISTICS TIME ON

SELECT 'UNION'
SELECT AnimalID, SUM(the_count) as total
FROM (
   SELECT AnimalID, COUNT(AnimalID) as the_count
   FROM animals1
   GROUP BY AnimalID
   UNION ALL
   SELECT AnimalID, COUNT(AnimalID) * -1 as the_count
   FROM animals2
   GROUP BY AnimalID) t
GROUP BY AnimalID

SELECT 'FULL OUTER JOIN'
SELECT  COALESCE(T1.AnimalId,T2.AnimalId) AS AnimalId,
        COALESCE(T1.Cnt,0) - COALESCE(T2.Cnt,0) Results
FROM
	(SELECT AnimalId, COUNT(AnimalId) Cnt FROM animals1 GROUP BY AnimalId) AS T1
FULL OUTER JOIN
	(SELECT AnimalId, COUNT(AnimalId) Cnt FROM animals2 GROUP BY AnimalId) T2
ON T2.AnimalId = T1.AnimalId
GO

Open in new window

0
 

Author Comment

by:ProdigyOne2k
ID: 39710403
Hey Jimhorn,,
I did not yet but i will check out your last post and let you know how it goes
Thanks!
0

Featured Post

Revamp Your Training Process

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I have a large data set and a SSIS package. How can I load this file in multi threading?
Introduction This article is intended for those who are new to PHP error handling (https://www.experts-exchange.com/articles/11769/And-by-the-way-I-am-New-to-PHP.html).  It addresses one of the most common problems that plague beginning PHP develop…
Familiarize people with the process of retrieving data from SQL Server using an Access pass-thru query. Microsoft Access is a very powerful client/server development tool. One of the ways that you can retrieve data from a SQL Server is by using a pa…
This video shows, step by step, how to configure Oracle Heterogeneous Services via the Generic Gateway Agent in order to make a connection from an Oracle session and access a remote SQL Server database table.

729 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question