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Add a join of a query

I have this query to compare values in two tables, Lindoc and ObrLinDoc.  Now i need join another table (Customers) to return in each line also Name and Id of customers.

SELECT
      	
       CodigoProduto
      , Designacao
      , CONVERT(DECIMAL(18,4),SUM(Quant_Orc))                                              AS [Quant Orcamentado]
      , CONVERT(DECIMAL(18,4),SUM(Quant_Imputado))                                         AS [Quant Imputado]
      , CONVERT(DECIMAL(18,4),SUM(Quant_Imputado)) - CONVERT(DECIMAL(18,4),SUM(Quant_Orc)) AS Desvio
	  , CONVERT(DECIMAL(18,2),sum (Venda_Imputado))                                        AS [Imputado Venda]  
	  , CONVERT(DECIMAL(18,2),sum (Custo_Imputado))                                        As [Imputado Custo]
FROM (
       
	    SELECT
              CodigoProduto
			  , '0' as mov
              , Designacao
              , SUM(quantidade)        AS Quant_Orc
              , 0                      AS Quant_Imputado 
			  , sum(TotalLinha)        As Venda_Imputado 
			  ,0                       AS Custo_Imputado
			 
        FROM lindoc
		     inner join cabdoc on
		     lindoc.IdStampCab=cabdoc.IdStamp
		WHERE CABdoc.TipoDoc='DO' and cabdoc.IdStamp='DOC20131015162329687'                   -- Preciso saber qual o numero documento
		 
		GROUP BY
              CodigoProduto
              , designacao
			 

        UNION ALL


                SELECT
                      CodigoProduto
					  , mov
                      , Designacao
                      , 0                                                                             AS Quant_Orc
					  , CASE mov WHEN 'S' THEN sum(quantidade) ELSE sum(quantidade)*-1                END AS Quant_Imputado
					  , 0                                                                             As Venda_Imputado 
			          , CASE mov WHEN 'S' THEN sum(TotalLinhaCusto) ELSE sum(TotalLinhaCusto)*-1 END  AS Custo_Imputado
                
				FROM ObrLinDoc
				WHERE CodigoObra=1                                      -- Preciso saber numero de obra
                GROUP BY
                        CodigoProduto
						,mov
                      , Designacao

     ) as ObrLin
	 Where CodigoProduto Is Not Null
	 
GROUP BY
         CodigoProduto
       , designacao

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rflorencio
Asked:
rflorencio
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1 Solution
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>Now i need join another table (Customers) to return in each line also Name and Id of customers.

Insert in line 52, and replace ?? with whatever column is the relationship between Customers and your subquery.  May need to add this column to the subquery if it doesn't already exists.
LEFT JOIN Customers c ON OrbLin.?? = c.??

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Then you can add to your SELECT clause,
,c.id as customer_id, c.name as customer_name

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rflorencioAuthor Commented:
I need join CustId but is in  Cabdoc.Custid table (line 23), can you help.
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>Cabdoc.Custid table (line 23)
table.column, so technically Cabdoc.Custid is a column.

In that case, you're going to have to add CustId to both SELECT statements in the UNION subquery.  Once that's done, the main query can use it in the LEFT JOIN.
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rflorencioAuthor Commented:
Hi  jimhorn, can you take a look to see if all is well, the result returned to me after running it seems correct.

SELECT
        CodCli
	  , NomeCli
	  , CodigoProduto
      , Designacao
      , CONVERT(DECIMAL(18,4),SUM(Quant_Orc))                                              AS [Quant Orcamentado]
      , CONVERT(DECIMAL(18,4),SUM(Quant_Imputado))                                         AS [Quant Imputado]
      , CONVERT(DECIMAL(18,4),SUM(Quant_Imputado)) - CONVERT(DECIMAL(18,4),SUM(Quant_Orc)) AS Desvio
	  , CONVERT(DECIMAL(18,2),sum (Venda_Imputado))                                        AS [Imputado Venda]  
	  , CONVERT(DECIMAL(18,2),sum (Custo_Imputado))                                        As [Imputado Custo]
FROM (
       
	    SELECT
		      clientes.CodigoCliente as CodCli
			  ,clientes.Nome as NomeCli	
              ,CodigoProduto
			  , '0' as mov
              , Designacao
              , SUM(quantidade)        AS Quant_Orc
              , 0                      AS Quant_Imputado 
			  , sum(TotalLinha)        As Venda_Imputado 
			  ,0                       AS Custo_Imputado
			 
        FROM lindoc
		     inner join cabdoc on lindoc.IdStampCab=cabdoc.IdStamp
			 inner join Clientes on CabDoc.CodigoEntidade=Clientes.CodigoCliente
		WHERE CABdoc.TipoDoc='DO' and cabdoc.IdStamp='DOC20131015162329687'                   -- Preciso saber qual o numero documento
		 
		GROUP BY
		
              CodigoProduto
              , designacao
			  , Clientes.CodigoCliente
			  , Clientes.Nome
			 

        UNION ALL


                SELECT
					  clientes.CodigoCliente as CodCli
					  ,clientes.Nome as NomeCli	
                      ,CodigoProduto
					  , ObrLinDoc.mov
                      , Designacao
                      , 0                                                                             AS Quant_Orc
					  , CASE ObrLinDoc.mov WHEN 'S' THEN sum(quantidade) ELSE sum(quantidade)*-1                END AS Quant_Imputado
					  , 0                                                                             As Venda_Imputado 
			          , CASE ObrLinDoc.mov WHEN 'S' THEN sum(TotalLinhaCusto) ELSE sum(TotalLinhaCusto)*-1 END  AS Custo_Imputado
                
				FROM ObrLinDoc
				 inner join ObrFichaObra on ObrLinDoc.CodigoObra=ObrFichaObra.CodigoObra
			     inner join Clientes on ObrFichaObra.CodigoCliente=Clientes.CodigoCliente
				WHERE ObrLinDoc.CodigoObra=1                                      -- Preciso saber numero de obra
                GROUP BY
                        CodigoProduto
						,ObrLinDoc.mov
                      , Designacao
					  , Clientes.CodigoCliente
			  , Clientes.Nome

     ) as ObrLin
	 Where CodigoProduto Is Not Null
	
GROUP BY
         CodigoProduto
       , designacao
	   , CodCli
	   , nomecli

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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Looks correct, although since I'm not connected to your data source I can't verify.
0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Thanks for the grade.  Good luck with your project.  -Jim
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