asked on

C# MSAccess - Already opened database

Hi,

I have been breaking my back on this one and just can't seem to figure out how to do this.
What I want to do is open up a database using C# and open up a form in the database with a specific filter that comes from C#.

This I got working perfectly with the code below:

Access.Application oAccess = new Access.Application();
oAccess.DoCmd.OpenForm("contacts", Access.AcFormView.acNormal, moMissing, "ID=2", Access.AcFormOpenDataMode.acFormPropertySettings ,Access.AcWindowMode.acWindowNormal, moMissing);

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The problem I am having now is every time I run the code it opens the database again even when it is already open. Causing 2 instances of the same database open.

My question is: How do I check if the database is already opened, then if so, don't open it again, rather give the form a new filter condition and refresh the results.

Is this at all possible?

Thanks in advance
S

TheAvenger

Keep the instance of the application as a member variable and before opening Access do this:

if (this.oAccess == null)
{
  // code to open
}
else
{
  // code to change filter
}

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PatHartman

You also have to close the form. I don't think the filer will be reapplied if the form is already open since it is used in the form's Load event which only runs once.

If I may ask, why are you opening a form? If you want data, you should be opening a recordset using either a query or a table.

SeanNij

ASKER

Hi Avenger.

I cannot use that logic, because what we want is a user to double click a .exe file.
Then the C# code in the exe file checks if the access database open already. If open close all open forms and reopen a form with specific filter.
So oAccess will never be null

Hi PatHartman,

The reason I need to open a form is because a user needs to click a button on the form to submit a result,

Thanks

Guy Hengel [angelIII / a3]

you didn't show the code, but you do use OpenCurrentDatabase, right?
what about the "exclusive" parameter, you use true there?

ASKER CERTIFIED SOLUTION

Dennis Aries

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SeanNij

ASKER

Exactly what I was looking for thanks!
Works like a charm!

Here is my working code:

                try
                {
                    oAccess = (Microsoft.Office.Interop.Access.Application)System.Runtime.InteropServices.Marshal.GetActiveObject("Access.Application");
                }
                catch
                {
                    oAccess = new Access.Application();
                }
                try
                {
// This fails if sDBPath is already open.
                    oAccess.OpenCurrentDatabase(sDBPath, false, "");
                }
                catch { }

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Thanks!!