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Drag excel formular and auto increment a number

Posted on 2013-12-13
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Last Modified: 2014-01-25
Hi all,

I am tring to copy the below code down in my exel spread sheet so it does the following
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),1)
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),2)
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),3)
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),4)
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),5)
------------------------------------------------------------------------------
=LARGE(IF(Result!$N$2:$N$1000=8,Result!$O$2:$O$1000,""),1)
=LARGE(IF(Result!$N$2:$N$1000=8,Result!$O$2:$O$1000,""),2)
=LARGE(IF(Result!$N$2:$N$1000=8,Result!$O$2:$O$1000,""),3)
=LARGE(IF(Result!$N$2:$N$1000=8,Result!$O$2:$O$1000,""),4)
=LARGE(IF(Result!$N$2:$N$1000=8,Result!$O$2:$O$1000,""),5)
------------------------------------------------------------------------------
(--- indicates a empty row)

I have tried to drap and drop it down so the number after Result!$N$2:$N$1000= increases each time but it just loops round!!!! any ideas how i can just copy it down???
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Question by:runnerjp2005
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6 Comments
 
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Expert Comment

by:Patrick Matthews
ID: 39717113
A sample worksheet would be helpful :)
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Accepted Solution

by:
Angelp1ay earned 250 total points
ID: 39717131
I would use Excel formulas to write those formulas, copy-paste the result out to notepad, and finally copy-paste back into a new column in Excel.

Round-tripping through notepad extracts the resultant text only on the way out and interprets as a formula on the way in.

See attachment for use and below code block for main concept...
=IF(A1<>"","=LARGE(IF(Result!$N$2:$N$1000="&A1&",Result!$O$2:$O$1000,""""),"&B1&")","")

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ComplexFormulaPaste.xlsx
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LVL 14

Assisted Solution

by:Faustulus
Faustulus earned 250 total points
ID: 39721095
Basically,
=MOD(ROW(),6)

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will do the job. It will produce the numbers 1 to 5 in rows 1:5, a zero in row 6 (which is blank in your worksheet) and resume with 1 thru 5 in row 7 etc.
If your first formula isn't in row 1 you should reduce the result returned by ROW() by a number equal to the number of rows above the first formula. For example,
=MOD(ROW()-2,6)

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would be the formula if the first of your formulas is in row 3.
Here is your formula with the above idea incorporated:-
=LARGE(IF(Result!$N$2:$N$1000=7,Result!$O$2:$O$1000,""),MOD(ROW()-2,6))

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LVL 14

Expert Comment

by:Faustulus
ID: 39721110
BTW, you could use a similar system to specify the result you are looking for - the 7 in
Result!$N$2:$N$1000=7.
This formula will count from 0 upward each 6 rows.
=INT(ROW()/6)

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Again, you can adjust the result to start counting at a row other than 1 in the manner already described. Similarly, if you need to start counting with 7 this formula would do the job, =7+INT(ROW()/6). Note that this method would return the wrong result for each row number divisible by 6. That can be compensated by enlarging the formula a little, but in your case that is not necessary because precisely those rows are blank.
Here is your formula with the above thought incorporated:-
=LARGE(IF(Result!$N$2:$N$1000=INT((ROW()-2)/6),Result!$O$2:$O$1000,""),MOD(ROW()-2,6))

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LVL 48

Expert Comment

by:Martin Liss
ID: 39808433
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
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