Solved

statement to remove everything after the first space in access query

Posted on 2013-12-16
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Last Modified: 2013-12-16
Hello.   I have a field (strength) that I just need the numbers at the beginning of the field and I want to strip off everything else.  The numbers are not the same length.  

Also - it is part of an Iff,then statement.  The IIf then statement is working, I need to find a wat just to get the first numbers of the field - and put it in my iif statement. The Strength field is the one that I need that data stripped from.

Here is an example of the data
Strength:
1000 MG = 26.32 ML
200 MG = 5.26 ML
10 MG = 1 TAB
1 CAP = 1 CAP

I want it to look like this:
1000
200
10
1



Dose: IIf([PDM].[Strength] Is Null Or [PDM].[Strength_Unit] Is Null,[PDM].[Volume_Number],[PDM].[Strength])
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Question by:joylene6
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18 Comments
 
LVL 58
ID: 39721646
Simple enough:

Dose:IIF(instr(Nz([Strength_Unit],"")," ")>1, Left(instr([Strength_Unit]," ")-1),[Strength_Unit])

Jim.
0
 
LVL 1

Author Comment

by:joylene6
ID: 39721702
Thanks- I will give it a try right now.
0
 
LVL 1

Author Comment

by:joylene6
ID: 39721754
I changed it to
 Dose1: IIf(InStr(Nz([PDM.Strength_Unit],"")," ")>1,Left(InStr([PDM.Strength_Unit]," ")-1,[PDM.Strength_Unit]))

But I am getting a data mismatch. The fields are text and I cannot change.  Does there need to have a VAL or something stuck in there to convert?
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LVL 32

Expert Comment

by:awking00
ID: 39721794
Replace
Left(InStr([PDM.Strength_Unit]," ")-1
with
Val(Left(InStr([PDM.Strength_Unit]," ")-1)
0
 
LVL 58
ID: 39721878
Should be:

 Dose1: IIf(InStr(Nz([PDM.Strength_Unit],"")," ")>1,Left(InStr([PDM.Strength_Unit]," ")-1),[PDM.Strength_Unit])

Jim.
0
 
LVL 58

Assisted Solution

by:Jim Dettman (Microsoft MVP/ EE MVE)
Jim Dettman (Microsoft MVP/ EE MVE) earned 250 total points
ID: 39721896
Whoops, missed an argument:

Dose1: IIf(InStr(Nz([PDM.Strength_Unit],"")," ")>1,Left([PDM.Strength_Unit],InStr([PDM.Strength_Unit]," ")-1),[PDM.Strength_Unit])

Sorry,
Jim.
0
 
LVL 120

Expert Comment

by:Rey Obrero (Capricorn1)
ID: 39721907
try this


try this


Dose1: IIf(InStr(Nz([PDM.Strength_Unit],"")," ")>1,Left([PDM.Strength_Unit], InStr([PDM.Strength_Unit]," ")-1),[PDM.Strength_Unit])

or this

Dose1: IIf(InStr(Nz([PDM].[Strength_Unit],"")," ")>1,Left([PDM].[Strength_Unit], InStr([PDM].[Strength_Unit]," ")-1),[PDM].[Strength_Unit])
0
 
LVL 1

Author Comment

by:joylene6
ID: 39721961
the Val(Left(InStr([PDM.Strength_Unit]," ")-1)  seems to have worked... but how do I add the VAL into the rest of the statement?

Dose1: IIf(InStr(Nz([PDM.Strength_Unit],"")," ")>1,Val(Left(InStr([PDM.Strength_Unit]," ")-1,[PDM.Strength_Unit])))
0
 
LVL 120

Expert Comment

by:Rey Obrero (Capricorn1)
ID: 39721978
if you want to use VAL(), you don't need the IIF() statement

Dose:Val([PDM.Strength_Unit])  

 is enough.. this will give the consecutive numerical values of the the field starting from position 1 and will stop when it finds a non numerical value


the last post of Jim should work.
0
 
LVL 32

Expert Comment

by:awking00
ID: 39722030
Didn't read the original question properly and only addressed the conversion to number issue.
Assuming you want to return the volume_number if either strength or strength_unit is null and the numeric portion of the strength otherwise -
IIf([PDM].[Strength] Is Null Or [PDM].[Strength_Unit] Is Null,[PDM].[Volume_Number],Val(Left(InStr([PDM.Strength]," ")-1)))
The above assumes the strength will always begin with a number followed by a space. If it can exist as a stand alone number, add the test Iif(instr(strength,' ') > 0,Val(Left(InStr([PDM.Strength]," ")-1),[PDM.Strength]))
0
 
LVL 1

Author Comment

by:joylene6
ID: 39722061
welll... I need an if then becasue if Strength_unit or Strength is blank then I need Volume number to populate.

This is what I used,  but it brought back all zeros instead of the number

Dose1: IIf(InStr(Nz([PDM.Strength],"")," ")>1,Val(Left(InStr([PDM.Strength_Unit]," ")-1,[PDM.Volume_Number])))

original field       What query brought back    what I expect
30 MG = 0.3 ML      0                                        30
30 MG = 0.3 ML      0                                        30
1 TAB = 1 TAB      0                                         1
1 TAB = 1 TAB      0                                         1
1 TAB = 1 TAB      0
0
 
LVL 32

Expert Comment

by:awking00
ID: 39722070
Using only val on this example , 10 MG = 1 TAB, I believe would produce 101.
0
 
LVL 120

Expert Comment

by:Rey Obrero (Capricorn1)
ID: 39722081
@joylene6,

if you read post at http:#a39721907  and http:#a39721896

you should not be using this

Dose1: IIf(InStr(Nz([PDM.Strength],"")," ")>1,Val(Left(InStr([PDM.Strength_Unit]," ")-1,[PDM.Volume_Number])))

which is WRONG.

please go back to posted comment and change your formula


.
0
 
LVL 120

Expert Comment

by:Rey Obrero (Capricorn1)
ID: 39722088
@awking00

<Using only val on this example , 10 MG = 1 TAB, I believe would produce 101. >
that is not correct

val("10 MG= 1 TAB")    will give you  10
0
 
LVL 32

Expert Comment

by:awking00
ID: 39722092
And what did this produce?
IIf([PDM].[Strength] Is Null Or [PDM].[Strength_Unit] Is Null,[PDM].[Volume_Number],Val(Left(InStr([PDM.Strength]," ")-1)))
0
 
LVL 32

Accepted Solution

by:
awking00 earned 250 total points
ID: 39722128
I stand corrected. So the statement just needs to be -
IIf([PDM].[Strength] Is Null Or [PDM].[Strength_Unit] Is Null,[PDM].[Volume_Number],Val[PDM.Strength])
0
 
LVL 1

Author Comment

by:joylene6
ID: 39722141
awkingoo- trying now
0
 
LVL 1

Author Comment

by:joylene6
ID: 39722174
awkingoo - that seemed to have worked.  Testing some more... but I think that was it.
0

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