Help with SQL

I have a table with "tasks" associated with a "job".  The tasks table has a foreign key that maps to the PK of the job table.   The task table has a description column.   I want a query that pulls back all task descriptions for job into a single concatenated text column, with the literal word "Task" and number that indicates the task order, based on the task date ASC, and the date.  With CrLf between each.   For example:

Task 1, 11/17/2013: The Task aaaaaa description.
Task 2, 11/23/2013: The Task bbbbbb description.
Task 3, 12/4/2013: The Task ccccc description.
Task 4, 12/13/2013: The Task ddddd description.
Who is Participating?
Scott PletcherConnect With a Mentor Senior DBACommented:
Something like this will do it:

SELECT j.column_name1, j.column_name2, --j....,
    (SELECT CAST('~' +
         'Task ' + CAST(t.task_number AS varchar(10)) + ' ' + CONVERT(varchar(10), t.task_date, 101) + ': ' + t.task_description
         AS varchar(8000))
     FROM dbo.tasks t
     WHERE t.job_key = j.job_key
     ORDER BY t.task_date
     FOR XML PATH('')
    ) AS varchar(8000)), 2, 8000), '~', CHAR(13) + CHAR(10)) AS Task_List
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
It would help if you can give us mockups of both the source of data, and the desired return set, as I'm not getting it from reading this question.
hnasrConnect With a Mentor Commented:
Compare with:
select  'Task ' + B.b +','+ B.x +':'+ B.r from A Inner join B On A.a=B.a;
(No column name)
Task 1,1:b11
Task 2,1:b12
Task 1,1:b21

For tables: A and B
a      r      x      n
1      a1      1      1.0
2      a2      1      2.0

a      b      r      x      n
1      1      b11      1      1.0
1      2      b12      1      2.0
2      1      b21      1      3.0

You may need to use cast and convert where necessary.
HLRosenbergerAuthor Commented:
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.